LTS Termination Proof

by AProVE

Input

Integer Transition System

Proof

1 Switch to Cooperation Termination Proof

We consider the following cutpoint-transitions:
f500_0_main_GE f500_0_main_GE f500_0_main_GE: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5
f493_0_rec4_LT f493_0_rec4_LT f493_0_rec4_LT: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5
f376_0_rec1_GT f376_0_rec1_GT f376_0_rec1_GT: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5
f1_0_main_ConstantStackPush f1_0_main_ConstantStackPush f1_0_main_ConstantStackPush: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5
f541_0_rec3_GT f541_0_rec3_GT f541_0_rec3_GT: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5
f323_0_rec0_GT f323_0_rec0_GT f323_0_rec0_GT: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5
f319_0_rec2_LT f319_0_rec2_LT f319_0_rec2_LT: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5
__init __init __init: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5
and for every transition t, a duplicate t is considered.

2 SCC Decomposition

We consider subproblems for each of the 6 SCC(s) of the program graph.

2.1 SCC Subproblem 1/6

Here we consider the SCC { f500_0_main_GE }.

2.1.1 Transition Removal

We remove transition 2 using the following ranking functions, which are bounded by 0.

f500_0_main_GE: x3x2

2.1.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.2 SCC Subproblem 2/6

Here we consider the SCC { f323_0_rec0_GT }.

2.2.1 Transition Removal

We remove transition 4 using the following ranking functions, which are bounded by 0.

f323_0_rec0_GT: x1 + x2

2.2.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.3 SCC Subproblem 3/6

Here we consider the SCC { f376_0_rec1_GT }.

2.3.1 Transition Removal

We remove transition 6 using the following ranking functions, which are bounded by 0.

f376_0_rec1_GT: x2 + x3

2.3.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.4 SCC Subproblem 4/6

Here we consider the SCC { f319_0_rec2_LT }.

2.4.1 Transition Removal

We remove transition 8 using the following ranking functions, which are bounded by 0.

f319_0_rec2_LT: x3

2.4.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.5 SCC Subproblem 5/6

Here we consider the SCC { f541_0_rec3_GT }.

2.5.1 Transition Removal

We remove transition 10 using the following ranking functions, which are bounded by 0.

f541_0_rec3_GT: x4 + x5

2.5.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.6 SCC Subproblem 6/6

Here we consider the SCC { f493_0_rec4_LT }.

2.6.1 Transition Removal

We remove transition 12 using the following ranking functions, which are bounded by 0.

f493_0_rec4_LT: x1

2.6.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

Tool configuration

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