LTS Termination Proof

by AProVE

Input

Integer Transition System

Proof

1 Switch to Cooperation Termination Proof

We consider the following cutpoint-transitions:
f765_0_insert_GT f765_0_insert_GT f765_0_insert_GT: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6
f1_0_main_Load f1_0_main_Load f1_0_main_Load: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6
f672_0_main_GE f672_0_main_GE f672_0_main_GE: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6
__init __init __init: x1 = x1x2 = x2x3 = x3x4 = x4x5 = x5x6 = x6
and for every transition t, a duplicate t is considered.

2 SCC Decomposition

We consider subproblems for each of the 2 SCC(s) of the program graph.

2.1 SCC Subproblem 1/2

Here we consider the SCC { f672_0_main_GE }.

2.1.1 Transition Removal

We remove transitions 2, 3 using the following ranking functions, which are bounded by 0.

f672_0_main_GE: x3 + x4

2.1.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

2.2 SCC Subproblem 2/2

Here we consider the SCC { f765_0_insert_GT }.

2.2.1 Transition Removal

We remove transitions 5, 6 using the following ranking functions, which are bounded by 0.

f765_0_insert_GT: x1

2.2.2 Trivial Cooperation Program

There are no more "sharp" transitions in the cooperation program. Hence the cooperation termination is proved.

Tool configuration

AProVE