Termination proof

1: switching to dependency pairs

The following set of initial dependency pairs has been identified.

f#( a , a ) f#( a , b )
f#( a , b ) f#( s( a ) , c )
f#( s( X ) , c ) f#( X , c )
f#( c , c ) f#( a , a )

1.1: reduction pair processor

Using the following reduction pair

Linear polynomial interpretation over the naturals
[b] = 0
[a] = 0
[f (x1, x2) ] = 3 x1
[c] = 1
[s (x1) ] = 2 x1
[f# (x1, x2) ] = x1
[f(x1, ..., xn)] = x1 + ... + xn + 1 for all other symbols f of arity n

one remains with the following pair(s).

f#( a , a ) f#( a , b )
f#( a , b ) f#( s( a ) , c )
f#( s( X ) , c ) f#( X , c )

1.1.1: dependency graph processor

The dependency pairs are split into 1 component(s).