Termination proof

1: switching to dependency pairs

The following set of initial dependency pairs has been identified.

active#( first( 0 , X ) ) mark#( nil )
active#( first( s( X ) , cons( Y , Z ) ) ) mark#( cons( Y , first( X , Z ) ) )
active#( first( s( X ) , cons( Y , Z ) ) ) cons#( Y , first( X , Z ) )
active#( first( s( X ) , cons( Y , Z ) ) ) first#( X , Z )
active#( from( X ) ) mark#( cons( X , from( s( X ) ) ) )
active#( from( X ) ) cons#( X , from( s( X ) ) )
active#( from( X ) ) from#( s( X ) )
active#( from( X ) ) s#( X )
mark#( first( X1 , X2 ) ) active#( first( mark( X1 ) , mark( X2 ) ) )
mark#( first( X1 , X2 ) ) first#( mark( X1 ) , mark( X2 ) )
mark#( first( X1 , X2 ) ) mark#( X1 )
mark#( first( X1 , X2 ) ) mark#( X2 )
mark#( 0 ) active#( 0 )
mark#( nil ) active#( nil )
mark#( s( X ) ) active#( s( mark( X ) ) )
mark#( s( X ) ) s#( mark( X ) )
mark#( s( X ) ) mark#( X )
mark#( cons( X1 , X2 ) ) active#( cons( mark( X1 ) , X2 ) )
mark#( cons( X1 , X2 ) ) cons#( mark( X1 ) , X2 )
mark#( cons( X1 , X2 ) ) mark#( X1 )
mark#( from( X ) ) active#( from( mark( X ) ) )
mark#( from( X ) ) from#( mark( X ) )
mark#( from( X ) ) mark#( X )
first#( mark( X1 ) , X2 ) first#( X1 , X2 )
first#( X1 , mark( X2 ) ) first#( X1 , X2 )
first#( active( X1 ) , X2 ) first#( X1 , X2 )
first#( X1 , active( X2 ) ) first#( X1 , X2 )
s#( mark( X ) ) s#( X )
s#( active( X ) ) s#( X )
cons#( mark( X1 ) , X2 ) cons#( X1 , X2 )
cons#( X1 , mark( X2 ) ) cons#( X1 , X2 )
cons#( active( X1 ) , X2 ) cons#( X1 , X2 )
cons#( X1 , active( X2 ) ) cons#( X1 , X2 )
from#( mark( X ) ) from#( X )
from#( active( X ) ) from#( X )

1.1: dependency graph processor

The dependency pairs are split into 5 component(s).