Termination proof

1: switching to dependency pairs

The following set of initial dependency pairs has been identified.

a__U11#( tt , L ) a__length#( mark( L ) )
a__U11#( tt , L ) mark#( L )
a__and#( tt , X ) mark#( X )
a__isNat#( length( V1 ) ) a__isNatList#( V1 )
a__isNat#( s( V1 ) ) a__isNat#( V1 )
a__isNatIList#( V ) a__isNatList#( V )
a__isNatIList#( cons( V1 , V2 ) ) a__and#( a__isNat( V1 ) , isNatIList( V2 ) )
a__isNatIList#( cons( V1 , V2 ) ) a__isNat#( V1 )
a__isNatList#( cons( V1 , V2 ) ) a__and#( a__isNat( V1 ) , isNatList( V2 ) )
a__isNatList#( cons( V1 , V2 ) ) a__isNat#( V1 )
a__length#( cons( N , L ) ) a__U11#( a__and( a__isNatList( L ) , isNat( N ) ) , L )
a__length#( cons( N , L ) ) a__and#( a__isNatList( L ) , isNat( N ) )
a__length#( cons( N , L ) ) a__isNatList#( L )
mark#( zeros ) a__zeros#
mark#( U11( X1 , X2 ) ) a__U11#( mark( X1 ) , X2 )
mark#( U11( X1 , X2 ) ) mark#( X1 )
mark#( length( X ) ) a__length#( mark( X ) )
mark#( length( X ) ) mark#( X )
mark#( and( X1 , X2 ) ) a__and#( mark( X1 ) , X2 )
mark#( and( X1 , X2 ) ) mark#( X1 )
mark#( isNat( X ) ) a__isNat#( X )
mark#( isNatList( X ) ) a__isNatList#( X )
mark#( isNatIList( X ) ) a__isNatIList#( X )
mark#( cons( X1 , X2 ) ) mark#( X1 )
mark#( s( X ) ) mark#( X )

1.1: dependency graph processor

The dependency pairs are split into 1 component(s).