Termination proof

1: switching to dependency pairs

The following set of initial dependency pairs has been identified.

active#( plus( N , s( M ) ) ) s#( plus( N , M ) )
active#( plus( N , s( M ) ) ) plus#( N , M )
active#( and( X1 , X2 ) ) and#( active( X1 ) , X2 )
active#( and( X1 , X2 ) ) active#( X1 )
active#( plus( X1 , X2 ) ) plus#( active( X1 ) , X2 )
active#( plus( X1 , X2 ) ) active#( X1 )
active#( plus( X1 , X2 ) ) plus#( X1 , active( X2 ) )
active#( plus( X1 , X2 ) ) active#( X2 )
active#( s( X ) ) s#( active( X ) )
active#( s( X ) ) active#( X )
and#( mark( X1 ) , X2 ) and#( X1 , X2 )
plus#( mark( X1 ) , X2 ) plus#( X1 , X2 )
plus#( X1 , mark( X2 ) ) plus#( X1 , X2 )
s#( mark( X ) ) s#( X )
proper#( and( X1 , X2 ) ) and#( proper( X1 ) , proper( X2 ) )
proper#( and( X1 , X2 ) ) proper#( X1 )
proper#( and( X1 , X2 ) ) proper#( X2 )
proper#( plus( X1 , X2 ) ) plus#( proper( X1 ) , proper( X2 ) )
proper#( plus( X1 , X2 ) ) proper#( X1 )
proper#( plus( X1 , X2 ) ) proper#( X2 )
proper#( s( X ) ) s#( proper( X ) )
proper#( s( X ) ) proper#( X )
and#( ok( X1 ) , ok( X2 ) ) and#( X1 , X2 )
plus#( ok( X1 ) , ok( X2 ) ) plus#( X1 , X2 )
s#( ok( X ) ) s#( X )
top#( mark( X ) ) top#( proper( X ) )
top#( mark( X ) ) proper#( X )
top#( ok( X ) ) top#( active( X ) )
top#( ok( X ) ) active#( X )

1.1: dependency graph processor

The dependency pairs are split into 6 component(s).