Certification Problem                    
                
Input (COPS 225)
We consider the TRS containing the following rules:
| 
f(a) | 
→ | 
b | 
(1) | 
| a | 
→ | 
a' | 
(2) | 
| 
f(b) | 
→ | 
c | 
(3) | 
The underlying signature is as follows:
{f/1, a/0, b/0, a'/0, c/0}Property / Task
Prove or disprove confluence.Answer / Result
No.Proof (by csi @ CoCo 2021)
1 Non-Joinable Fork
        The system is not confluent due to the following forking derivations.  
        
            
        The two resulting terms cannot be joined for the following reason:
        - 
        The reachable terms of these two terms are approximated via the following two tree automata,
        and the tree automata have an empty intersection.
        
- 
Automaton 1
- 
final states:
{1}
 
- 
transitions:
 
                The automaton is closed under rewriting as it is compatible.
             
- 
Automaton 2
- 
final states:
{3}
 
- 
transitions:
 
                The automaton is closed under rewriting as it is compatible.