Certification Problem                    
                
Input (TPDB SRS_Standard/Zantema_04/z104)
The rewrite relation of the following TRS is considered.
| 
c(c(c(a(x1)))) | 
→ | 
d(d(x1)) | 
(1) | 
| 
d(b(x1)) | 
→ | 
c(c(x1)) | 
(2) | 
| 
c(x1) | 
→ | 
a(a(a(a(x1)))) | 
(3) | 
| 
d(x1) | 
→ | 
b(b(b(b(x1)))) | 
(4) | 
| 
b(d(x1)) | 
→ | 
c(c(x1)) | 
(5) | 
| 
a(c(c(c(x1)))) | 
→ | 
d(d(x1)) | 
(6) | 
Property / Task
Prove or disprove termination.Answer / Result
Yes.Proof (by NaTT @ termCOMP 2023)
1 Dependency Pair Transformation
          The following set of initial dependency pairs has been identified.
          
| 
d#(b(x1)) | 
→ | 
c#(x1) | 
(7) | 
| 
b#(d(x1)) | 
→ | 
c#(x1) | 
(8) | 
| 
d#(x1) | 
→ | 
b#(b(b(b(x1)))) | 
(9) | 
| 
c#(x1) | 
→ | 
a#(a(x1)) | 
(10) | 
| 
c#(c(c(a(x1)))) | 
→ | 
d#(d(x1)) | 
(11) | 
| 
c#(c(c(a(x1)))) | 
→ | 
d#(x1) | 
(12) | 
| 
d#(x1) | 
→ | 
b#(b(b(x1))) | 
(13) | 
| 
c#(x1) | 
→ | 
a#(a(a(a(x1)))) | 
(14) | 
| 
c#(x1) | 
→ | 
a#(x1) | 
(15) | 
| 
b#(d(x1)) | 
→ | 
c#(c(x1)) | 
(16) | 
| 
d#(x1) | 
→ | 
b#(x1) | 
(17) | 
| 
a#(c(c(c(x1)))) | 
→ | 
d#(d(x1)) | 
(18) | 
| 
d#(b(x1)) | 
→ | 
c#(c(x1)) | 
(19) | 
| 
c#(x1) | 
→ | 
a#(a(a(x1))) | 
(20) | 
| 
d#(x1) | 
→ | 
b#(b(x1)) | 
(21) | 
| 
a#(c(c(c(x1)))) | 
→ | 
d#(x1) | 
(22) | 
1.1 Dependency Graph Processor
The dependency pairs are split into 1
        component.