Certification Problem                    
                
Input (TPDB SRS_Standard/Zantema_06/15)
The rewrite relation of the following TRS is considered.
| 
a(x1) | 
→ | 
b(x1) | 
(1) | 
| 
a(a(x1)) | 
→ | 
a(b(a(x1))) | 
(2) | 
| 
a(b(x1)) | 
→ | 
b(b(b(x1))) | 
(3) | 
| 
a(a(a(x1))) | 
→ | 
a(a(b(a(a(x1))))) | 
(4) | 
| 
a(a(b(x1))) | 
→ | 
a(b(b(a(b(x1))))) | 
(5) | 
| 
a(b(a(x1))) | 
→ | 
b(a(b(b(a(x1))))) | 
(6) | 
| 
a(b(b(x1))) | 
→ | 
b(b(b(b(b(x1))))) | 
(7) | 
| 
a(a(a(a(x1)))) | 
→ | 
a(a(a(b(a(a(a(x1))))))) | 
(8) | 
| 
a(a(a(b(x1)))) | 
→ | 
a(a(b(b(a(a(b(x1))))))) | 
(9) | 
| 
a(a(b(a(x1)))) | 
→ | 
a(b(a(b(a(b(a(x1))))))) | 
(10) | 
| 
a(a(b(b(x1)))) | 
→ | 
a(b(b(b(a(b(b(x1))))))) | 
(11) | 
| 
a(b(a(a(x1)))) | 
→ | 
b(a(a(b(b(a(a(x1))))))) | 
(12) | 
| 
a(b(a(b(x1)))) | 
→ | 
b(a(b(b(b(a(b(x1))))))) | 
(13) | 
| 
a(b(b(a(x1)))) | 
→ | 
b(b(a(b(b(b(a(x1))))))) | 
(14) | 
| 
a(b(b(b(x1)))) | 
→ | 
b(b(b(b(b(b(b(x1))))))) | 
(15) | 
Property / Task
Prove or disprove termination.Answer / Result
Yes.Proof (by NaTT @ termCOMP 2023)
1 Dependency Pair Transformation
          The following set of initial dependency pairs has been identified.
          
| 
a#(b(a(x1))) | 
→ | 
a#(b(b(a(x1)))) | 
(16) | 
| 
a#(a(b(b(x1)))) | 
→ | 
a#(b(b(b(a(b(b(x1))))))) | 
(17) | 
| 
a#(a(a(a(x1)))) | 
→ | 
a#(a(a(b(a(a(a(x1))))))) | 
(18) | 
| 
a#(b(b(a(x1)))) | 
→ | 
a#(b(b(b(a(x1))))) | 
(19) | 
| 
a#(a(b(a(x1)))) | 
→ | 
a#(b(a(b(a(x1))))) | 
(20) | 
| 
a#(a(b(x1))) | 
→ | 
a#(b(b(a(b(x1))))) | 
(21) | 
| 
a#(a(a(a(x1)))) | 
→ | 
a#(a(b(a(a(a(x1)))))) | 
(22) | 
| 
a#(b(a(a(x1)))) | 
→ | 
a#(a(b(b(a(a(x1)))))) | 
(23) | 
| 
a#(a(b(a(x1)))) | 
→ | 
a#(b(a(b(a(b(a(x1))))))) | 
(24) | 
| 
a#(a(a(b(x1)))) | 
→ | 
a#(b(b(a(a(b(x1)))))) | 
(25) | 
| 
a#(a(a(x1))) | 
→ | 
a#(b(a(a(x1)))) | 
(26) | 
| 
a#(a(a(x1))) | 
→ | 
a#(a(b(a(a(x1))))) | 
(27) | 
| 
a#(b(a(b(x1)))) | 
→ | 
a#(b(b(b(a(b(x1)))))) | 
(28) | 
| 
a#(a(x1)) | 
→ | 
a#(b(a(x1))) | 
(29) | 
| 
a#(b(a(a(x1)))) | 
→ | 
a#(b(b(a(a(x1))))) | 
(30) | 
| 
a#(a(a(a(x1)))) | 
→ | 
a#(b(a(a(a(x1))))) | 
(31) | 
| 
a#(a(a(b(x1)))) | 
→ | 
a#(a(b(b(a(a(b(x1))))))) | 
(32) | 
1.1 Dependency Graph Processor
The dependency pairs are split into 1
        component.