Certification Problem

Input (TPDB SRS_Standard/Waldmann_07_size12/size-12-alpha-3-num-373)

The rewrite relation of the following TRS is considered.

a(x1) b(x1) (1)
a(c(x1)) x1 (2)
c(b(b(x1))) a(a(a(c(c(x1))))) (3)

Property / Task

Prove or disprove termination.

Answer / Result

No.

Proof (by matchbox @ termCOMP 2023)

1 Loop

The following loop proves nontermination.

t0 = c(c(b(b(b(b(c(c(x1))))))))
c(a(a(a(c(c(b(b(c(c(x1))))))))))
c(a(a(b(c(c(b(b(c(c(x1))))))))))
c(a(b(b(c(c(b(b(c(c(x1))))))))))
c(b(b(b(c(c(b(b(c(c(x1))))))))))
c(b(b(b(c(a(a(a(c(c(c(c(x1))))))))))))
c(b(b(b(c(a(a(c(c(c(x1))))))))))
c(b(b(b(c(a(b(c(c(c(x1))))))))))
c(b(b(b(c(b(b(c(c(c(x1))))))))))
c(b(b(b(a(a(a(c(c(c(c(c(x1))))))))))))
c(b(b(b(a(a(b(c(c(c(c(c(x1))))))))))))
c(b(b(b(a(b(b(c(c(c(c(c(x1))))))))))))
c(b(b(b(b(b(b(c(c(c(c(c(x1))))))))))))
a(a(a(c(c(b(b(b(b(c(c(c(c(c(x1))))))))))))))
= t13
where t13 = C[t0σ] and σ = {x1/c(c(c(x1)))} and C = a(a(a()))