Certification Problem

Input (TPDB SRS_Standard/Zantema_06/14)

The rewrite relation of the following TRS is considered.

a(a(x1)) b(a(b(x1))) (1)
b(b(x1)) a(c(b(x1))) (2)
c(c(x1)) c(b(a(x1))) (3)
a(b(x1)) b(a(x1)) (4)
b(c(x1)) c(x1) (5)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by matchbox @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
c#(c(x1)) c#(b(a(x1))) (6)
c#(c(x1)) b#(a(x1)) (7)
c#(c(x1)) a#(x1) (8)
b#(b(x1)) c#(b(x1)) (9)
b#(b(x1)) a#(c(b(x1))) (10)
a#(b(x1)) b#(a(x1)) (11)
a#(b(x1)) a#(x1) (12)
a#(a(x1)) b#(x1) (13)
a#(a(x1)) b#(a(b(x1))) (14)
a#(a(x1)) a#(b(x1)) (15)

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.