Certification Problem

Input (TPDB SRS_Standard/Wenzel_16/abababaab-aababaabababab.srs)

The rewrite relation of the following TRS is considered.

a(b(a(b(a(b(a(a(b(x1))))))))) a(a(b(a(b(a(a(b(a(b(a(b(a(b(x1)))))))))))))) (1)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by ttt2 @ termCOMP 2023)

1 Semantic Labeling

Root-labeling is applied.

We obtain the labeled TRS
ab(ba(ab(ba(ab(ba(aa(ab(ba(x1))))))))) aa(ab(ba(ab(ba(aa(ab(ba(ab(ba(ab(ba(ab(ba(x1)))))))))))))) (2)
ab(ba(ab(ba(ab(ba(aa(ab(bb(x1))))))))) aa(ab(ba(ab(ba(aa(ab(ba(ab(ba(ab(ba(ab(bb(x1)))))))))))))) (3)

1.1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
ab#(ba(ab(ba(ab(ba(aa(ab(ba(x1))))))))) ab#(ba(ab(ba(x1)))) (4)
ab#(ba(ab(ba(ab(ba(aa(ab(ba(x1))))))))) ab#(ba(ab(ba(ab(ba(x1)))))) (5)
ab#(ba(ab(ba(ab(ba(aa(ab(ba(x1))))))))) ab#(ba(ab(ba(ab(ba(ab(ba(x1)))))))) (6)
ab#(ba(ab(ba(ab(ba(aa(ab(ba(x1))))))))) ab#(ba(aa(ab(ba(ab(ba(ab(ba(ab(ba(x1))))))))))) (7)
ab#(ba(ab(ba(ab(ba(aa(ab(ba(x1))))))))) ab#(ba(ab(ba(aa(ab(ba(ab(ba(ab(ba(ab(ba(x1))))))))))))) (8)
ab#(ba(ab(ba(ab(ba(aa(ab(bb(x1))))))))) ab#(ba(ab(bb(x1)))) (9)
ab#(ba(ab(ba(ab(ba(aa(ab(bb(x1))))))))) ab#(ba(ab(ba(ab(bb(x1)))))) (10)
ab#(ba(ab(ba(ab(ba(aa(ab(bb(x1))))))))) ab#(ba(ab(ba(ab(ba(ab(bb(x1)))))))) (11)
ab#(ba(ab(ba(ab(ba(aa(ab(bb(x1))))))))) ab#(ba(aa(ab(ba(ab(ba(ab(ba(ab(bb(x1))))))))))) (12)
ab#(ba(ab(ba(ab(ba(aa(ab(bb(x1))))))))) ab#(ba(ab(ba(aa(ab(ba(ab(ba(ab(ba(ab(bb(x1))))))))))))) (13)

1.1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.