Certification Problem

Input (TPDB TRS_Innermost/Transformed_CSR_innermost_04/Ex24_GM04_GM)

The rewrite relation of the following TRS is considered.

a__f(X,g(X),Y) a__f(Y,Y,Y) (1)
a__g(b) c (2)
a__b c (3)
mark(f(X1,X2,X3)) a__f(X1,X2,X3) (4)
mark(g(X)) a__g(mark(X)) (5)
mark(b) a__b (6)
mark(c) c (7)
a__f(X1,X2,X3) f(X1,X2,X3) (8)
a__g(X) g(X) (9)
a__b b (10)
The evaluation strategy is innermost.

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by AProVE @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
a__f#(X,g(X),Y) a__f#(Y,Y,Y) (11)
mark#(f(X1,X2,X3)) a__f#(X1,X2,X3) (12)
mark#(g(X)) a__g#(mark(X)) (13)
mark#(g(X)) mark#(X) (14)
mark#(b) a__b# (15)

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.