The rewrite relation of the following TRS is considered.
| a(b(a(x))) | → | b(a(b(x))) | (1) | 
| a#(b(a(x))) | → | a#(b(x)) | (2) | 
The dependency pairs are split into 1 component.
| a#(b(a(x))) | → | a#(b(x)) | (2) | 
| [a(x1)] | = | x1 + 1 | 
| [b(x1)] | = | x1 + 28958 | 
| [a#(x1)] | = | x1 + 0 | 
| a#(b(a(x))) | → | a#(b(x)) | (2) | 
The dependency pairs are split into 0 components.