Certification Problem

Input (TPDB TRS_Standard/Transformed_CSR_04/LISTUTILITIES_nokinds_L)

The rewrite relation of the following TRS is considered.

U101(tt) fst(splitAt(N,XS)) (1)
U11(tt) snd(splitAt(N,XS)) (2)
U21(tt) X (3)
U31(tt) N (4)
U41(tt) cons(N) (5)
U51(tt) head(afterNth(N,XS)) (6)
U61(tt) Y (7)
U71(tt) pair(nil,XS) (8)
U81(tt) U82(splitAt(N,XS)) (9)
U82(pair(YS,ZS)) pair(cons(X),ZS) (10)
U91(tt) XS (11)
and(tt) X (12)
afterNth(N,XS) U11(and(isNatural)) (13)
fst(pair(X,Y)) U21(and(isLNat)) (14)
head(cons(N)) U31(and(isNatural)) (15)
isLNat tt (16)
isLNat and(isNatural) (17)
isLNat isPLNat (18)
isLNat isNatural (19)
isLNat isLNat (20)
isNatural tt (21)
isNatural isLNat (22)
isNatural isNatural (23)
isNatural and(isNatural) (24)
isPLNat and(isLNat) (25)
isPLNat and(isNatural) (26)
natsFrom(N) U41(isNatural) (27)
sel(N,XS) U51(and(isNatural)) (28)
snd(pair(X,Y)) U61(and(isLNat)) (29)
splitAt(0,XS) U71(isLNat) (30)
splitAt(s(N),cons(X)) U81(and(isNatural)) (31)
tail(cons(N)) U91(and(isNatural)) (32)
take(N,XS) U101(and(isNatural)) (33)

Property / Task

Prove or disprove termination.

Answer / Result

No.

Proof (by ttt2 @ termCOMP 2023)

1 Loop

The following loop proves nontermination.

t0 = U101(tt)
fst(splitAt(U101(tt),XS))
= t1
where t1 = C[t0σ] and σ = {N/U101(tt)} and C = fst(splitAt(,XS))