MAYBE We are left with following problem, upon which TcT provides the certificate MAYBE. Strict Trs: { minus(x, x) -> 0() , minus(x, 0()) -> x , minus(0(), x) -> 0() , minus(s(x), s(y)) -> minus(x, y) , le(0(), y) -> true() , le(s(x), 0()) -> false() , le(s(x), s(y)) -> le(x, y) , quot(x, y) -> if_quot(minus(x, y), y, le(y, 0()), le(y, x)) , if_quot(x, y, true(), z) -> divByZeroError() , if_quot(x, y, false(), true()) -> s(quot(x, y)) , if_quot(x, y, false(), false()) -> 0() } Obligation: runtime complexity Answer: MAYBE None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'Best' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'WithProblem (timeout of 30 seconds) (timeout of 60 seconds)' failed due to the following reason: Computation stopped due to timeout after 30.0 seconds. 2) 'Fastest (timeout of 5 seconds) (timeout of 60 seconds)' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'Bounds with minimal-enrichment and initial automaton 'match'' failed due to the following reason: match-boundness of the problem could not be verified. 2) 'Bounds with perSymbol-enrichment and initial automaton 'match'' failed due to the following reason: match-boundness of the problem could not be verified. 3) 'Best' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'Polynomial Path Order (PS) (timeout of 60 seconds)' failed due to the following reason: The processor is inapplicable, reason: Processor only applicable for innermost runtime complexity analysis 2) 'bsearch-popstar (timeout of 60 seconds)' failed due to the following reason: The processor is inapplicable, reason: Processor only applicable for innermost runtime complexity analysis 2) 'Innermost Weak Dependency Pairs (timeout of 60 seconds)' failed due to the following reason: We add the following weak dependency pairs: Strict DPs: { minus^#(x, x) -> c_1() , minus^#(x, 0()) -> c_2(x) , minus^#(0(), x) -> c_3() , minus^#(s(x), s(y)) -> c_4(minus^#(x, y)) , le^#(0(), y) -> c_5() , le^#(s(x), 0()) -> c_6() , le^#(s(x), s(y)) -> c_7(le^#(x, y)) , quot^#(x, y) -> c_8(if_quot^#(minus(x, y), y, le(y, 0()), le(y, x))) , if_quot^#(x, y, true(), z) -> c_9() , if_quot^#(x, y, false(), true()) -> c_10(quot^#(x, y)) , if_quot^#(x, y, false(), false()) -> c_11() } and mark the set of starting terms. We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { minus^#(x, x) -> c_1() , minus^#(x, 0()) -> c_2(x) , minus^#(0(), x) -> c_3() , minus^#(s(x), s(y)) -> c_4(minus^#(x, y)) , le^#(0(), y) -> c_5() , le^#(s(x), 0()) -> c_6() , le^#(s(x), s(y)) -> c_7(le^#(x, y)) , quot^#(x, y) -> c_8(if_quot^#(minus(x, y), y, le(y, 0()), le(y, x))) , if_quot^#(x, y, true(), z) -> c_9() , if_quot^#(x, y, false(), true()) -> c_10(quot^#(x, y)) , if_quot^#(x, y, false(), false()) -> c_11() } Strict Trs: { minus(x, x) -> 0() , minus(x, 0()) -> x , minus(0(), x) -> 0() , minus(s(x), s(y)) -> minus(x, y) , le(0(), y) -> true() , le(s(x), 0()) -> false() , le(s(x), s(y)) -> le(x, y) , quot(x, y) -> if_quot(minus(x, y), y, le(y, 0()), le(y, x)) , if_quot(x, y, true(), z) -> divByZeroError() , if_quot(x, y, false(), true()) -> s(quot(x, y)) , if_quot(x, y, false(), false()) -> 0() } Obligation: runtime complexity Answer: MAYBE We estimate the number of application of {1,3,5,6,9,11} by applications of Pre({1,3,5,6,9,11}) = {2,4,7,8}. Here rules are labeled as follows: DPs: { 1: minus^#(x, x) -> c_1() , 2: minus^#(x, 0()) -> c_2(x) , 3: minus^#(0(), x) -> c_3() , 4: minus^#(s(x), s(y)) -> c_4(minus^#(x, y)) , 5: le^#(0(), y) -> c_5() , 6: le^#(s(x), 0()) -> c_6() , 7: le^#(s(x), s(y)) -> c_7(le^#(x, y)) , 8: quot^#(x, y) -> c_8(if_quot^#(minus(x, y), y, le(y, 0()), le(y, x))) , 9: if_quot^#(x, y, true(), z) -> c_9() , 10: if_quot^#(x, y, false(), true()) -> c_10(quot^#(x, y)) , 11: if_quot^#(x, y, false(), false()) -> c_11() } We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { minus^#(x, 0()) -> c_2(x) , minus^#(s(x), s(y)) -> c_4(minus^#(x, y)) , le^#(s(x), s(y)) -> c_7(le^#(x, y)) , quot^#(x, y) -> c_8(if_quot^#(minus(x, y), y, le(y, 0()), le(y, x))) , if_quot^#(x, y, false(), true()) -> c_10(quot^#(x, y)) } Strict Trs: { minus(x, x) -> 0() , minus(x, 0()) -> x , minus(0(), x) -> 0() , minus(s(x), s(y)) -> minus(x, y) , le(0(), y) -> true() , le(s(x), 0()) -> false() , le(s(x), s(y)) -> le(x, y) , quot(x, y) -> if_quot(minus(x, y), y, le(y, 0()), le(y, x)) , if_quot(x, y, true(), z) -> divByZeroError() , if_quot(x, y, false(), true()) -> s(quot(x, y)) , if_quot(x, y, false(), false()) -> 0() } Weak DPs: { minus^#(x, x) -> c_1() , minus^#(0(), x) -> c_3() , le^#(0(), y) -> c_5() , le^#(s(x), 0()) -> c_6() , if_quot^#(x, y, true(), z) -> c_9() , if_quot^#(x, y, false(), false()) -> c_11() } Obligation: runtime complexity Answer: MAYBE Empty strict component of the problem is NOT empty. Arrrr..