0.00/0.77	YES
0.00/0.77	
0.00/0.77	Problem:
0.00/0.77	f(x) -> y <= x = y
0.00/0.77	a() -> b()
0.00/0.77	b() -> c()
0.00/0.77	
0.00/0.77	Proof:
0.00/0.77	This system is confluent.
0.00/0.77	By \cite{ALS94}, Theorem 4.1.
0.00/0.77	This system is of type 3 or smaller.
0.00/0.77	This system is strongly deterministic.
0.00/0.77	All 0 critical pairs are joinable.
0.00/0.77	This system is quasi-decreasing.
0.00/0.77	By \cite{O02}, p. 214, Proposition 7.2.50.
0.00/0.77	This system is of type 3 or smaller.
0.00/0.77	This system is deterministic.
0.00/0.77	System R transformed to U(R).
0.00/0.77	This system is terminating.
0.00/0.77	Call external tool:
0.00/0.77	./ttt2.sh
0.00/0.77	Input:
0.00/0.77	  ?1(y, x) -> y
0.00/0.77	  f(x) -> ?1(x, x)
0.00/0.77	  a() -> b()
0.00/0.77	  b() -> c()
0.00/0.77	
0.00/0.77	 Polynomial Interpretation Processor:
0.00/0.77	  dimension: 1
0.00/0.77	  interpretation:
0.00/0.77	   [c] = 0,
0.00/0.77	   
0.00/0.77	   [b] = 4,
0.00/0.77	   
0.00/0.77	   [a] = 5,
0.00/0.78	   
0.00/0.78	   [f](x0) = 4x0 + 2x0x0 + 5,
0.00/0.78	   
0.00/0.78	   [?1](x0, x1) = x0 + 2x1x1 + 4
0.00/0.78	  orientation:
0.00/0.78	   ?1(y,x) = 2x*x + y + 4 >= y = y
0.00/0.78	   
0.00/0.78	   f(x) = 4x + 2x*x + 5 >= x + 2x*x + 4 = ?1(x,x)
0.00/0.78	   
0.00/0.78	   a() = 5 >= 4 = b()
0.00/0.78	   
0.00/0.78	   b() = 4 >= 0 = c()
0.00/0.78	  problem:
0.00/0.78	   
0.00/0.78	  Qed
0.00/0.78	
0.00/0.78	EOF