0.00/0.50	MAYBE
0.00/0.50	
0.00/0.50	Problem:
0.00/0.50	f(x) -> a() <= x = b()
0.00/0.50	a() -> b()
0.00/0.50	a() -> c()
0.00/0.50	
0.00/0.50	Proof:
0.00/0.51	ConCon could not decide confluence of the system.
0.00/0.51	\cite{ALS94}, Theorem 4.1 does not apply.
0.00/0.51	ConCon could not decide whether all 2 critical pairs are joinable or not.
0.00/0.51	CP: b() = c():
0.00/0.51	
0.00/0.51	EOF