MAYBE

Proof:
ConCon could not decide confluence of the system.
\cite{ALS94}, Theorem 4.1 does not apply.
ConCon could not decide whether all critical pairs are joinable or not.
pair(0, x) = pair(s(y), $1) <= leq(x, $2) = true, div(m($2, x), x) = pair(y, $1), greater(x, $2) = true:
For all conditions c 'tcap(c.lhs)' is unifiable with c.rhs.
\cite{GNG13}, Theorem 9 does not apply.
\cite{SMI95}, Corollary 4.7 or 5.3 do not apply.
Some critical pairs are not trivial and ConCon could not decide whether those all are infeasible.
pair(0, x) = pair(s(y), $1) <= leq(x, $2) = true, div(m($2, x), x) = pair(y, $1), greater(x, $2) = true:
For all conditions c 'tcap(c.lhs)' is unifiable with c.rhs.