Problem: f(x,x) -> h(x,x) c() -> h(c(),g(c())) h(g3(x),g1(g2(x))) -> f(x,h(x,g(x))) Proof: Church Rosser Transformation Processor (to relative problem): strict: f(x,x) -> h(x,x) c() -> h(c(),g(c())) h(g3(x),g1(g2(x))) -> f(x,h(x,g(x))) weak: original problem: f(x,x) -> h(x,x) c() -> h(c(),g(c())) h(g3(x),g1(g2(x))) -> f(x,h(x,g(x))) critical peaks: Matrix Interpretation Processor: dim=1 interpretation: [g1](x0) = x0 + 6, [g2](x0) = 2x0, [g3](x0) = x0 + 2, [g](x0) = x0, [c] = 0, [h](x0, x1) = x0 + x1, [f](x0, x1) = x0 + x1 orientation: f(x,x) = 2x >= 2x = h(x,x) c() = 0 >= 0 = h(c(),g(c())) h(g3(x),g1(g2(x))) = 3x + 8 >= 3x = f(x,h(x,g(x))) problem: strict: f(x,x) -> h(x,x) c() -> h(c(),g(c())) weak: original problem: f(x,x) -> h(x,x) c() -> h(c(),g(c())) h(g3(x),g1(g2(x))) -> f(x,h(x,g(x))) Polynomial Interpretation Processor: dimension: 1 interpretation: [g](x0) = 2x0x0, [c] = 0, [h](x0, x1) = x1 + x0x0, [f](x0, x1) = x0 + 2x0x0 + 2x0x1 + 2x1x1 + 1 orientation: f(x,x) = x + 6x*x + 1 >= x + x*x = h(x,x) c() = 0 >= 0 = h(c(),g(c())) problem: strict: c() -> h(c(),g(c())) weak: original problem: f(x,x) -> h(x,x) c() -> h(c(),g(c())) h(g3(x),g1(g2(x))) -> f(x,h(x,g(x))) KH confluence processor Split input TRS into two TRSs S and T: TRS S: c() -> h(c(),g(c())) TRS T: f(x,x) -> h(x,x) h(g3(x),g1(g2(x))) -> f(x,h(x,g(x))) As established above, T/S is terminating. T is strongly non-overlapping on S and S is strongly non-overlapping on T Please install theorem prover 'Prover9' and 'Mace4' for handling more TRSs. All S-critical pairs are joinable. We have to check confluence of S. Church Rosser Transformation Processor (no redundant rules): strict: c() -> h(c(),g(c())) weak: critical peaks: 0 Closedness Processor (*feeble*): Qed