Problem:
 b() -> a()
 a() -> f(h(b(),a()))
 h(a(),h(f(h(c(),b())),b())) -> f(a())
 h(a(),b()) -> c()

Proof:
 Nonconfluence Processor:
  terms: h(f(h(b(),a())),h(f(h(c(),b())),b())) *<- h(a(),h(f(h(c(),b())),b())) ->* 
  f(a())
  Qed