The rewrite relation of the following TRS is considered.
a(x1) | → | x1 | (1) |
a(b(x1)) | → | c(x1) | (2) |
a(c(c(x1))) | → | c(b(a(c(a(x1))))) | (3) |
a(x1) | → | x1 | (1) |
b(a(x1)) | → | c(x1) | (4) |
c(c(a(x1))) | → | a(c(a(b(c(x1))))) | (5) |
b#(a(x1)) | → | c#(x1) | (6) |
c#(c(a(x1))) | → | a#(c(a(b(c(x1))))) | (7) |
c#(c(a(x1))) | → | c#(a(b(c(x1)))) | (8) |
c#(c(a(x1))) | → | a#(b(c(x1))) | (9) |
c#(c(a(x1))) | → | b#(c(x1)) | (10) |
c#(c(a(x1))) | → | c#(x1) | (11) |
The dependency pairs are split into 1 component.
c#(c(a(x1))) | → | c#(a(b(c(x1)))) | (8) |
c#(c(a(x1))) | → | b#(c(x1)) | (10) |
b#(a(x1)) | → | c#(x1) | (6) |
c#(c(a(x1))) | → | c#(x1) | (11) |
[c#(x1)] | = |
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[c(x1)] | = |
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[a(x1)] | = |
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[b(x1)] | = |
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[b#(x1)] | = |
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c#(c(a(x1))) | → | b#(c(x1)) | (10) |
The dependency pairs are split into 1 component.
c#(c(a(x1))) | → | c#(x1) | (11) |
c#(c(a(x1))) | → | c#(a(b(c(x1)))) | (8) |
[c#(x1)] | = |
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[c(x1)] | = |
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[a(x1)] | = |
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[b(x1)] | = |
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c#(c(a(x1))) | → | c#(x1) | (11) |
c#(c(a(x1))) | → | c#(a(b(c(x1)))) | (8) |
There are no pairs anymore.