Certification Problem

Input (TPDB SRS_Standard/Waldmann_07_size12/size-12-alpha-3-num-465)

The rewrite relation of the following TRS is considered.

Property / Task

Answer / Result

Proof (by AProVE @ termCOMP 2023)

1 Dependency Pair Transformation

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.

• The 1^st component contains the pair

  c#(c(b(x1)))	→	c#(x1)	(7)
  c#(c(b(x1)))	→	c#(c(x1))	(6)

  1.1.1 Reduction Pair Processor

  Using the matrix interpretations of dimension 3 with strict dimension 1 over the arctic semiring over the naturals

  [c#(x1)]	=	0 -∞ -∞ + 0 -∞ 0 -∞ -∞ -∞ -∞ -∞ -∞ · x1
  [c(x1)]	=	0 0 0 + -∞ 0 -∞ 0 -∞ 0 -∞ 0 -∞ · x1
  [b(x1)]	=	0 1 0 + -∞ 0 -∞ 0 1 0 -∞ 0 -∞ · x1
  [a(x1)]	=	0 1 0 + -∞ 0 -∞ 0 1 0 -∞ 0 -∞ · x1

  the pair

  c#(c(b(x1)))

  →

  c#(c(x1))

  (6)

  could be deleted.

  1.1.1.1 Monotonic Reduction Pair Processor with Usable Rules

  Using the linear polynomial interpretation over the naturals

  [c(x1)]	=	1 · x1
  [b(x1)]	=	1 · x1
  [c#(x1)]	=	1 · x1

  having no usable rules (w.r.t. the implicit argument filter of the reduction pair), the rule could be deleted.

  1.1.1.1.1 Size-Change Termination

  Using size-change termination in combination with the subterm criterion one obtains the following initial size-change graphs.

  c#(c(b(x1)))	→	c#(x1)	(7)
  1	>	1

  As there is no critical graph in the transitive closure, there are no infinite chains.