Certification Problem
Input (TPDB SRS_Standard/Zantema_04/z012)
The rewrite relation of the following TRS is considered.
|
a(x1) |
→ |
b(x1) |
(1) |
|
a(b(x1)) |
→ |
b(c(a(x1))) |
(2) |
|
b(x1) |
→ |
c(x1) |
(3) |
|
c(b(x1)) |
→ |
a(x1) |
(4) |
Property / Task
Prove or disprove termination.Answer / Result
Yes.Proof (by AProVE @ termCOMP 2023)
1 Rule Removal
Using the
linear polynomial interpretation over the naturals
| [a(x1)] |
= |
1 · x1 + 1 |
| [b(x1)] |
= |
1 · x1 + 1 |
| [c(x1)] |
= |
1 · x1
|
all of the following rules can be deleted.
1.1 Dependency Pair Transformation
The following set of initial dependency pairs has been identified.
|
a#(b(x1)) |
→ |
c#(a(x1)) |
(5) |
|
a#(b(x1)) |
→ |
a#(x1) |
(6) |
|
c#(b(x1)) |
→ |
a#(x1) |
(7) |
1.1.1 Monotonic Reduction Pair Processor
Using the linear polynomial interpretation over the naturals
| [a(x1)] |
= |
2 + 1 · x1
|
| [b(x1)] |
= |
2 + 1 · x1
|
| [c(x1)] |
= |
1 · x1
|
| [a#(x1)] |
= |
3 + 2 · x1
|
| [c#(x1)] |
= |
2 · x1
|
the
pairs
|
a#(b(x1)) |
→ |
c#(a(x1)) |
(5) |
|
a#(b(x1)) |
→ |
a#(x1) |
(6) |
|
c#(b(x1)) |
→ |
a#(x1) |
(7) |
and
no rules
could be deleted.
1.1.1.1 P is empty
There are no pairs anymore.