Certification Problem

Input (TPDB SRS_Standard/ICFP_2010/157593)

The rewrite relation of the following TRS is considered.

0(0(0(1(x1)))) 0(1(0(0(2(3(x1)))))) (1)
0(0(4(1(x1)))) 4(2(0(1(0(x1))))) (2)
0(0(4(1(x1)))) 0(2(1(4(2(0(x1)))))) (3)
0(0(4(1(x1)))) 1(0(5(4(2(0(x1)))))) (4)
0(0(4(1(x1)))) 3(4(2(0(1(0(x1)))))) (5)
0(3(4(0(x1)))) 0(3(0(2(4(2(x1)))))) (6)
0(3(4(0(x1)))) 0(3(4(2(0(2(x1)))))) (7)
0(3(4(0(x1)))) 0(4(5(3(0(5(x1)))))) (8)
0(4(4(0(x1)))) 4(4(2(0(0(x1))))) (9)
0(4(4(0(x1)))) 0(4(0(2(4(2(x1)))))) (10)
0(4(4(0(x1)))) 4(2(0(0(2(4(x1)))))) (11)
0(4(4(0(x1)))) 4(2(0(0(4(2(x1)))))) (12)
0(4(4(0(x1)))) 4(2(0(4(2(0(x1)))))) (13)
0(4(4(1(x1)))) 0(1(4(4(2(x1))))) (14)
0(4(4(1(x1)))) 1(4(4(2(0(x1))))) (15)
0(4(4(1(x1)))) 0(1(4(4(2(3(x1)))))) (16)
0(4(4(1(x1)))) 0(1(5(4(4(2(x1)))))) (17)
0(4(4(1(x1)))) 1(5(4(4(2(0(x1)))))) (18)
0(4(4(1(x1)))) 2(4(0(1(5(4(x1)))))) (19)
0(4(4(1(x1)))) 2(4(4(1(2(0(x1)))))) (20)
0(4(4(1(x1)))) 2(4(5(4(0(1(x1)))))) (21)
0(4(4(1(x1)))) 4(2(4(2(1(0(x1)))))) (22)
1(4(4(0(x1)))) 5(4(4(2(0(1(x1)))))) (23)
1(4(4(1(x1)))) 2(1(4(1(2(4(x1)))))) (24)
1(4(4(1(x1)))) 2(3(4(1(4(1(x1)))))) (25)
1(4(4(1(x1)))) 2(4(1(2(1(4(x1)))))) (26)
1(4(4(1(x1)))) 2(4(2(1(4(1(x1)))))) (27)
4(0(0(0(x1)))) 0(4(2(0(0(5(x1)))))) (28)
4(0(0(1(x1)))) 2(3(0(1(0(4(x1)))))) (29)
4(0(4(0(x1)))) 2(4(2(0(0(4(x1)))))) (30)
4(0(4(0(x1)))) 3(4(2(0(4(0(x1)))))) (31)
4(0(4(1(x1)))) 2(4(2(0(4(1(x1)))))) (32)
4(3(4(0(x1)))) 4(0(3(4(2(x1))))) (33)
4(3(4(0(x1)))) 4(4(2(0(3(x1))))) (34)
4(3(4(0(x1)))) 0(4(2(3(4(2(x1)))))) (35)
4(3(4(0(x1)))) 2(3(0(4(4(5(x1)))))) (36)
4(3(4(0(x1)))) 2(3(4(4(0(2(x1)))))) (37)
4(3(4(0(x1)))) 2(4(0(3(4(2(x1)))))) (38)
4(3(4(0(x1)))) 4(2(0(4(2(3(x1)))))) (39)
4(3(4(0(x1)))) 4(3(0(5(4(2(x1)))))) (40)
4(3(4(0(x1)))) 4(4(2(3(0(2(x1)))))) (41)
4(3(4(0(x1)))) 4(4(5(3(0(3(x1)))))) (42)
4(3(4(1(x1)))) 3(4(2(4(1(x1))))) (43)
4(3(4(1(x1)))) 1(4(2(4(2(3(x1)))))) (44)
4(3(4(1(x1)))) 2(3(1(4(5(4(x1)))))) (45)
4(3(4(1(x1)))) 2(3(4(2(1(4(x1)))))) (46)
4(3(4(1(x1)))) 2(4(2(3(1(4(x1)))))) (47)
4(3(4(1(x1)))) 3(1(4(2(4(2(x1)))))) (48)
4(3(4(1(x1)))) 3(4(2(4(5(1(x1)))))) (49)
4(3(4(1(x1)))) 3(4(5(3(4(1(x1)))))) (50)
4(4(4(0(x1)))) 2(4(2(4(4(0(x1)))))) (51)
4(4(4(1(x1)))) 2(4(2(4(1(4(x1)))))) (52)
4(4(4(1(x1)))) 4(2(4(1(2(4(x1)))))) (53)
4(4(4(1(x1)))) 4(5(4(1(5(4(x1)))))) (54)
0(0(4(0(0(x1))))) 0(4(2(0(0(0(x1)))))) (55)
0(1(3(5(0(x1))))) 0(1(3(0(5(3(x1)))))) (56)
0(3(4(0(0(x1))))) 3(4(2(0(0(0(x1)))))) (57)
0(3(5(0(1(x1))))) 0(1(0(5(2(3(x1)))))) (58)
0(3(5(4(1(x1))))) 5(1(0(4(5(3(x1)))))) (59)
0(4(3(4(0(x1))))) 0(2(3(4(4(0(x1)))))) (60)
1(4(4(0(0(x1))))) 4(1(4(2(0(0(x1)))))) (61)
1(4(4(0(1(x1))))) 1(4(4(1(2(0(x1)))))) (62)
1(4(4(4(1(x1))))) 2(4(1(4(4(1(x1)))))) (63)
4(0(0(4(1(x1))))) 4(4(2(0(1(0(x1)))))) (64)
4(0(4(4(0(x1))))) 4(0(4(2(4(0(x1)))))) (65)
4(1(0(0(1(x1))))) 4(2(0(1(1(0(x1)))))) (66)
4(1(3(4(0(x1))))) 3(1(4(2(4(0(x1)))))) (67)
4(3(1(0(0(x1))))) 1(4(2(3(0(0(x1)))))) (68)
4(3(1(0(0(x1))))) 3(1(4(2(0(0(x1)))))) (69)
4(3(1(5(0(x1))))) 1(4(5(3(0(1(x1)))))) (70)
4(3(2(4(0(x1))))) 4(2(0(3(4(2(x1)))))) (71)
4(3(4(4(1(x1))))) 4(4(3(1(4(2(x1)))))) (72)
4(3(5(0(0(x1))))) 4(0(5(2(3(0(x1)))))) (73)
4(3(5(0(1(x1))))) 2(3(5(4(0(1(x1)))))) (74)
4(3(5(4(0(x1))))) 0(3(4(5(4(5(x1)))))) (75)
4(3(5(4(0(x1))))) 0(4(5(3(4(2(x1)))))) (76)
4(3(5(4(0(x1))))) 4(4(5(3(0(2(x1)))))) (77)
4(3(5(4(0(x1))))) 5(4(3(4(2(0(x1)))))) (78)
4(3(5(4(1(x1))))) 3(4(2(4(5(1(x1)))))) (79)
4(3(5(5(0(x1))))) 0(2(3(5(4(5(x1)))))) (80)
4(3(5(5(1(x1))))) 1(5(4(2(5(3(x1)))))) (81)
4(4(0(0(1(x1))))) 4(0(4(2(0(1(x1)))))) (82)
4(4(4(4(1(x1))))) 4(4(4(1(2(4(x1)))))) (83)
4(4(5(0(1(x1))))) 4(5(0(1(4(2(x1)))))) (84)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by NaTT @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.

There are 262 ruless (increase limit for explicit display).

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.