Certification Problem

Input (TPDB SRS_Standard/ICFP_2010/4046)

The rewrite relation of the following TRS is considered.

4(2(4(x1))) 2(0(0(5(3(3(5(2(0(4(x1)))))))))) (1)
4(4(2(4(2(x1))))) 2(0(5(2(1(4(0(2(0(1(x1)))))))))) (2)
0(5(4(2(4(3(x1)))))) 5(1(5(5(3(5(3(0(0(0(x1)))))))))) (3)
1(1(4(5(3(3(x1)))))) 1(3(1(1(3(0(1(2(2(1(x1)))))))))) (4)
3(1(4(3(1(2(x1)))))) 0(0(1(1(4(2(3(0(0(3(x1)))))))))) (5)
3(2(4(2(4(1(x1)))))) 0(2(1(1(1(5(3(1(3(3(x1)))))))))) (6)
3(3(0(4(1(2(x1)))))) 3(5(1(2(0(2(0(5(3(1(x1)))))))))) (7)
4(1(4(5(0(5(4(x1))))))) 4(1(5(3(1(0(5(3(1(0(x1)))))))))) (8)
4(4(0(5(4(2(2(x1))))))) 4(0(4(3(4(4(4(5(4(1(x1)))))))))) (9)
5(4(5(3(2(4(3(x1))))))) 2(5(5(5(0(4(5(0(1(4(x1)))))))))) (10)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by NaTT @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
4#(4(2(4(2(x1))))) 5#(2(1(4(0(2(0(1(x1)))))))) (11)
1#(1(4(5(3(3(x1)))))) 1#(2(2(1(x1)))) (12)
5#(4(5(3(2(4(3(x1))))))) 4#(x1) (13)
3#(3(0(4(1(2(x1)))))) 1#(2(0(2(0(5(3(1(x1)))))))) (14)
5#(4(5(3(2(4(3(x1))))))) 5#(5(5(0(4(5(0(1(4(x1))))))))) (15)
1#(1(4(5(3(3(x1)))))) 1#(3(0(1(2(2(1(x1))))))) (16)
4#(2(4(x1))) 3#(3(5(2(0(4(x1)))))) (17)
3#(1(4(3(1(2(x1)))))) 1#(1(4(2(3(0(0(3(x1)))))))) (18)
5#(4(5(3(2(4(3(x1))))))) 1#(4(x1)) (19)
5#(4(5(3(2(4(3(x1))))))) 0#(1(4(x1))) (20)
5#(4(5(3(2(4(3(x1))))))) 5#(0(4(5(0(1(4(x1))))))) (21)
4#(1(4(5(0(5(4(x1))))))) 3#(1(0(5(3(1(0(x1))))))) (22)
3#(1(4(3(1(2(x1)))))) 1#(4(2(3(0(0(3(x1))))))) (23)
0#(5(4(2(4(3(x1)))))) 5#(1(5(5(3(5(3(0(0(0(x1)))))))))) (24)
4#(1(4(5(0(5(4(x1))))))) 1#(5(3(1(0(5(3(1(0(x1))))))))) (25)
3#(1(4(3(1(2(x1)))))) 4#(2(3(0(0(3(x1)))))) (26)
4#(1(4(5(0(5(4(x1))))))) 0#(5(3(1(0(x1))))) (27)
4#(1(4(5(0(5(4(x1))))))) 1#(0(5(3(1(0(x1)))))) (28)
0#(5(4(2(4(3(x1)))))) 5#(3(0(0(0(x1))))) (29)
0#(5(4(2(4(3(x1)))))) 0#(0(x1)) (30)
5#(4(5(3(2(4(3(x1))))))) 0#(4(5(0(1(4(x1)))))) (31)
4#(4(2(4(2(x1))))) 0#(1(x1)) (32)
0#(5(4(2(4(3(x1)))))) 3#(0(0(0(x1)))) (33)
0#(5(4(2(4(3(x1)))))) 5#(5(3(5(3(0(0(0(x1)))))))) (34)
4#(2(4(x1))) 3#(5(2(0(4(x1))))) (35)
5#(4(5(3(2(4(3(x1))))))) 5#(0(1(4(x1)))) (36)
3#(1(4(3(1(2(x1)))))) 0#(3(x1)) (37)
3#(2(4(2(4(1(x1)))))) 3#(1(3(3(x1)))) (38)
3#(2(4(2(4(1(x1)))))) 1#(1(1(5(3(1(3(3(x1)))))))) (39)
3#(2(4(2(4(1(x1)))))) 1#(5(3(1(3(3(x1)))))) (40)
0#(5(4(2(4(3(x1)))))) 3#(5(3(0(0(0(x1)))))) (41)
4#(1(4(5(0(5(4(x1))))))) 5#(3(1(0(x1)))) (42)
4#(4(0(5(4(2(2(x1))))))) 5#(4(1(x1))) (43)
4#(1(4(5(0(5(4(x1))))))) 4#(1(5(3(1(0(5(3(1(0(x1)))))))))) (44)
4#(4(0(5(4(2(2(x1))))))) 4#(5(4(1(x1)))) (45)
1#(1(4(5(3(3(x1)))))) 3#(1(1(3(0(1(2(2(1(x1))))))))) (46)
4#(1(4(5(0(5(4(x1))))))) 1#(0(x1)) (47)
3#(1(4(3(1(2(x1)))))) 0#(1(1(4(2(3(0(0(3(x1))))))))) (48)
4#(2(4(x1))) 0#(4(x1)) (49)
3#(2(4(2(4(1(x1)))))) 5#(3(1(3(3(x1))))) (50)
3#(3(0(4(1(2(x1)))))) 0#(5(3(1(x1)))) (51)
4#(1(4(5(0(5(4(x1))))))) 0#(x1) (52)
0#(5(4(2(4(3(x1)))))) 5#(3(5(3(0(0(0(x1))))))) (53)
1#(1(4(5(3(3(x1)))))) 1#(1(3(0(1(2(2(1(x1)))))))) (54)
3#(2(4(2(4(1(x1)))))) 1#(3(3(x1))) (55)
0#(5(4(2(4(3(x1)))))) 0#(x1) (56)
3#(3(0(4(1(2(x1)))))) 0#(2(0(5(3(1(x1)))))) (57)
3#(1(4(3(1(2(x1)))))) 3#(x1) (58)
3#(1(4(3(1(2(x1)))))) 3#(0(0(3(x1)))) (59)
4#(4(0(5(4(2(2(x1))))))) 4#(1(x1)) (60)
4#(4(0(5(4(2(2(x1))))))) 3#(4(4(4(5(4(1(x1))))))) (61)
4#(4(2(4(2(x1))))) 1#(x1) (62)
5#(4(5(3(2(4(3(x1))))))) 4#(5(0(1(4(x1))))) (63)
3#(2(4(2(4(1(x1)))))) 1#(1(5(3(1(3(3(x1))))))) (64)
4#(2(4(x1))) 0#(5(3(3(5(2(0(4(x1)))))))) (65)
3#(3(0(4(1(2(x1)))))) 3#(1(x1)) (66)
4#(1(4(5(0(5(4(x1))))))) 5#(3(1(0(5(3(1(0(x1)))))))) (67)
4#(4(2(4(2(x1))))) 0#(2(0(1(x1)))) (68)
3#(1(4(3(1(2(x1)))))) 0#(0(1(1(4(2(3(0(0(3(x1)))))))))) (69)
4#(2(4(x1))) 5#(3(3(5(2(0(4(x1))))))) (70)
3#(3(0(4(1(2(x1)))))) 5#(1(2(0(2(0(5(3(1(x1))))))))) (71)
4#(4(0(5(4(2(2(x1))))))) 4#(4(5(4(1(x1))))) (72)
3#(3(0(4(1(2(x1)))))) 1#(x1) (73)
1#(1(4(5(3(3(x1)))))) 3#(0(1(2(2(1(x1)))))) (74)
1#(1(4(5(3(3(x1)))))) 1#(x1) (75)
3#(3(0(4(1(2(x1)))))) 3#(5(1(2(0(2(0(5(3(1(x1)))))))))) (76)
0#(5(4(2(4(3(x1)))))) 0#(0(0(x1))) (77)
4#(4(0(5(4(2(2(x1))))))) 4#(0(4(3(4(4(4(5(4(1(x1)))))))))) (78)
3#(3(0(4(1(2(x1)))))) 5#(3(1(x1))) (79)
4#(4(0(5(4(2(2(x1))))))) 4#(3(4(4(4(5(4(1(x1)))))))) (80)
4#(2(4(x1))) 0#(0(5(3(3(5(2(0(4(x1))))))))) (81)
4#(4(0(5(4(2(2(x1))))))) 1#(x1) (82)
1#(1(4(5(3(3(x1)))))) 0#(1(2(2(1(x1))))) (83)
4#(2(4(x1))) 5#(2(0(4(x1)))) (84)
5#(4(5(3(2(4(3(x1))))))) 5#(5(0(4(5(0(1(4(x1)))))))) (85)
4#(4(0(5(4(2(2(x1))))))) 4#(4(4(5(4(1(x1)))))) (86)
3#(2(4(2(4(1(x1)))))) 3#(x1) (87)
4#(4(2(4(2(x1))))) 1#(4(0(2(0(1(x1)))))) (88)
4#(1(4(5(0(5(4(x1))))))) 3#(1(0(x1))) (89)
4#(4(2(4(2(x1))))) 0#(5(2(1(4(0(2(0(1(x1))))))))) (90)
0#(5(4(2(4(3(x1)))))) 1#(5(5(3(5(3(0(0(0(x1))))))))) (91)
3#(2(4(2(4(1(x1)))))) 0#(2(1(1(1(5(3(1(3(3(x1)))))))))) (92)
3#(2(4(2(4(1(x1)))))) 3#(3(x1)) (93)
4#(4(2(4(2(x1))))) 4#(0(2(0(1(x1))))) (94)
1#(1(4(5(3(3(x1)))))) 1#(3(1(1(3(0(1(2(2(1(x1)))))))))) (95)
3#(1(4(3(1(2(x1)))))) 0#(0(3(x1))) (96)
4#(4(0(5(4(2(2(x1))))))) 0#(4(3(4(4(4(5(4(1(x1))))))))) (97)

1.1 Dependency Graph Processor

The dependency pairs are split into 2 components.