Certification Problem

Input (TPDB SRS_Standard/Secret_06_SRS/5)

The rewrite relation of the following TRS is considered.

a(a(a(x1))) a(a(b(b(x1)))) (1)
b(b(b(b(x1)))) a(b(a(a(x1)))) (2)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by matchbox @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
b#(b(b(b(x1)))) b#(a(a(x1))) (3)
b#(b(b(b(x1)))) a#(x1) (4)
b#(b(b(b(x1)))) a#(b(a(a(x1)))) (5)
b#(b(b(b(x1)))) a#(a(x1)) (6)
a#(a(a(x1))) b#(x1) (7)
a#(a(a(x1))) b#(b(x1)) (8)
a#(a(a(x1))) a#(b(b(x1))) (9)
a#(a(a(x1))) a#(a(b(b(x1)))) (10)

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.