Certification Problem

Input (TPDB SRS_Standard/Waldmann_07_size12/size-12-alpha-3-num-279)

The rewrite relation of the following TRS is considered.

a(x1) x1 (1)
a(b(x1)) c(b(x1)) (2)
b(x1) a(a(c(x1))) (3)
c(c(x1)) b(x1) (4)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by ttt2 @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
a#(b(x1)) c#(b(x1)) (5)
b#(x1) c#(x1) (6)
b#(x1) a#(c(x1)) (7)
b#(x1) a#(a(c(x1))) (8)
c#(c(x1)) b#(x1) (9)

1.1 Reduction Pair Processor with Usable Rules

Using the linear polynomial interpretation over (2 x 2)-matrices with strict dimension 1 over the arctic semiring over the integers
[c#(x1)] =
2 1
-∞ -∞
· x1 +
0 -∞
-∞ -∞
[b(x1)] =
1 0
2 1
· x1 +
0 -∞
1 -∞
[a#(x1)] =
0 1
-∞ -∞
· x1 +
0 -∞
-∞ -∞
[b#(x1)] =
3 2
-∞ -∞
· x1 +
1 -∞
-∞ -∞
[a(x1)] =
0 0
0 0
· x1 +
0 -∞
0 -∞
[c(x1)] =
1 0
1 0
· x1 +
0 -∞
-∞ -∞
together with the usable rules
a(x1) x1 (1)
a(b(x1)) c(b(x1)) (2)
b(x1) a(a(c(x1))) (3)
c(c(x1)) b(x1) (4)
(w.r.t. the implicit argument filter of the reduction pair), the pairs
b#(x1) c#(x1) (6)
b#(x1) a#(c(x1)) (7)
could be deleted.

1.1.1 Reduction Pair Processor with Usable Rules

Using the linear polynomial interpretation over (2 x 2)-matrices with strict dimension 1 over the arctic semiring over the integers
[c#(x1)] =
-∞ 2
-∞ -∞
· x1 +
0 -∞
-∞ -∞
[b(x1)] =
0 1
0 1
· x1 +
1 -∞
1 -∞
[a#(x1)] =
2 0
-∞ -∞
· x1 +
0 -∞
-∞ -∞
[b#(x1)] =
1 3
-∞ -∞
· x1 +
3 -∞
-∞ -∞
[a(x1)] =
0 -∞
1 0
· x1 +
0 -∞
0 -∞
[c(x1)] =
-∞ 0
0 1
· x1 +
0 -∞
1 -∞
together with the usable rules
a(x1) x1 (1)
a(b(x1)) c(b(x1)) (2)
b(x1) a(a(c(x1))) (3)
c(c(x1)) b(x1) (4)
(w.r.t. the implicit argument filter of the reduction pair), the pair
b#(x1) a#(a(c(x1))) (8)
could be deleted.

1.1.1.1 Dependency Graph Processor

The dependency pairs are split into 0 components.