Certification Problem

Input (TPDB TRS_Outermost/Strategy_outermost_added_08/OvConsOS_nosorts-noand_Z)

The rewrite relation of the following TRS is considered.

zeros cons(0,n__zeros) (1)
U11(tt,L) U12(tt,activate(L)) (2)
U12(tt,L) s(length(activate(L))) (3)
U21(tt,IL,M,N) U22(tt,activate(IL),activate(M),activate(N)) (4)
U22(tt,IL,M,N) U23(tt,activate(IL),activate(M),activate(N)) (5)
U23(tt,IL,M,N) cons(activate(N),n__take(activate(M),activate(IL))) (6)
length(nil) 0 (7)
length(cons(N,L)) U11(tt,activate(L)) (8)
take(0,IL) nil (9)
take(s(M),cons(N,IL)) U21(tt,activate(IL),M,N) (10)
zeros n__zeros (11)
take(X1,X2) n__take(X1,X2) (12)
activate(n__zeros) zeros (13)
activate(n__take(X1,X2)) take(X1,X2) (14)
activate(X) X (15)
The evaluation strategy is outermost

Property / Task

Prove or disprove termination.

Answer / Result

No.

Proof (by AProVE @ termCOMP 2023)

1 Loop

The following loop proves nontermination.

t0 = U12(tt,activate(activate(n__zeros)))
s(length(activate(activate(activate(n__zeros)))))
s(length(activate(activate(n__zeros))))
s(length(activate(n__zeros)))
s(length(zeros))
s(length(cons(0,n__zeros)))
s(U11(tt,activate(n__zeros)))
s(U12(tt,activate(activate(n__zeros))))
= t7
where t7 = C[t0] and C = s()