The rewrite relation of the following TRS is considered.
U61(tt) | → | s(length(L)) | (1) |
and(tt) | → | X | (2) |
zeros | → | cons(0) | (3) |
U11(tt) | → | U12(isNatList) | (4) |
U12(tt) | → | tt | (5) |
U21(tt) | → | U22(isNat) | (6) |
U22(tt) | → | tt | (7) |
U31(tt) | → | U32(isNatList) | (8) |
U32(tt) | → | tt | (9) |
U41(tt) | → | U42(isNat) | (10) |
U42(tt) | → | U43(isNatIList) | (11) |
U43(tt) | → | tt | (12) |
U51(tt) | → | U52(isNat) | (13) |
U52(tt) | → | U53(isNatList) | (14) |
U53(tt) | → | tt | (15) |
isNat | → | tt | (16) |
isNat | → | U11(isNatIListKind) | (17) |
isNat | → | U21(isNatKind) | (18) |
isNatIList | → | U31(isNatIListKind) | (19) |
isNatIList | → | tt | (20) |
isNatIList | → | U41(and(isNatKind)) | (21) |
isNatIListKind | → | tt | (22) |
isNatIListKind | → | and(isNatKind) | (23) |
isNatKind | → | tt | (24) |
isNatKind | → | isNatIListKind | (25) |
isNatKind | → | isNatKind | (26) |
isNatList | → | tt | (27) |
isNatList | → | U51(and(isNatKind)) | (28) |
length(nil) | → | 0 | (29) |
length(cons(N)) | → | U61(and(and(isNatList))) | (30) |
The TRS violates one of the two variable conditions. Thus, it is not terminating.