Certification Problem

Input (TPDB TRS_Standard/Transformed_CSR_04/Ex3_12_Luc96a_GM)

The rewrite relation of the following TRS is considered.

a__from(X) cons(mark(X),from(s(X))) (1)
a__sel(0,cons(X,Y)) mark(X) (2)
a__sel(s(X),cons(Y,Z)) a__sel(mark(X),mark(Z)) (3)
mark(from(X)) a__from(mark(X)) (4)
mark(sel(X1,X2)) a__sel(mark(X1),mark(X2)) (5)
mark(cons(X1,X2)) cons(mark(X1),X2) (6)
mark(s(X)) s(mark(X)) (7)
mark(0) 0 (8)
a__from(X) from(X) (9)
a__sel(X1,X2) sel(X1,X2) (10)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by NaTT @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
mark#(cons(X1,X2)) mark#(X1) (11)
mark#(sel(X1,X2)) mark#(X2) (12)
a__sel#(s(X),cons(Y,Z)) mark#(Z) (13)
mark#(from(X)) a__from#(mark(X)) (14)
mark#(from(X)) mark#(X) (15)
a__sel#(s(X),cons(Y,Z)) a__sel#(mark(X),mark(Z)) (16)
a__from#(X) mark#(X) (17)
mark#(sel(X1,X2)) mark#(X1) (18)
mark#(s(X)) mark#(X) (19)
a__sel#(0,cons(X,Y)) mark#(X) (20)
a__sel#(s(X),cons(Y,Z)) mark#(X) (21)
mark#(sel(X1,X2)) a__sel#(mark(X1),mark(X2)) (22)

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.