Certification Problem

Input (TPDB TRS_Standard/Transformed_CSR_04/Ex4_DLMMU04_GM)

The rewrite relation of the following TRS is considered.

a__and(tt,T) mark(T) (1)
a__isNatIList(IL) a__isNatList(IL) (2)
a__isNat(0) tt (3)
a__isNat(s(N)) a__isNat(N) (4)
a__isNat(length(L)) a__isNatList(L) (5)
a__isNatIList(zeros) tt (6)
a__isNatIList(cons(N,IL)) a__and(a__isNat(N),a__isNatIList(IL)) (7)
a__isNatList(nil) tt (8)
a__isNatList(cons(N,L)) a__and(a__isNat(N),a__isNatList(L)) (9)
a__isNatList(take(N,IL)) a__and(a__isNat(N),a__isNatIList(IL)) (10)
a__zeros cons(0,zeros) (11)
a__take(0,IL) a__uTake1(a__isNatIList(IL)) (12)
a__uTake1(tt) nil (13)
a__take(s(M),cons(N,IL)) a__uTake2(a__and(a__isNat(M),a__and(a__isNat(N),a__isNatIList(IL))),M,N,IL) (14)
a__uTake2(tt,M,N,IL) cons(mark(N),take(M,IL)) (15)
a__length(cons(N,L)) a__uLength(a__and(a__isNat(N),a__isNatList(L)),L) (16)
a__uLength(tt,L) s(a__length(mark(L))) (17)
mark(and(X1,X2)) a__and(mark(X1),mark(X2)) (18)
mark(isNatIList(X)) a__isNatIList(X) (19)
mark(isNatList(X)) a__isNatList(X) (20)
mark(isNat(X)) a__isNat(X) (21)
mark(length(X)) a__length(mark(X)) (22)
mark(zeros) a__zeros (23)
mark(take(X1,X2)) a__take(mark(X1),mark(X2)) (24)
mark(uTake1(X)) a__uTake1(mark(X)) (25)
mark(uTake2(X1,X2,X3,X4)) a__uTake2(mark(X1),X2,X3,X4) (26)
mark(uLength(X1,X2)) a__uLength(mark(X1),X2) (27)
mark(tt) tt (28)
mark(0) 0 (29)
mark(s(X)) s(mark(X)) (30)
mark(cons(X1,X2)) cons(mark(X1),X2) (31)
mark(nil) nil (32)
a__and(X1,X2) and(X1,X2) (33)
a__isNatIList(X) isNatIList(X) (34)
a__isNatList(X) isNatList(X) (35)
a__isNat(X) isNat(X) (36)
a__length(X) length(X) (37)
a__zeros zeros (38)
a__take(X1,X2) take(X1,X2) (39)
a__uTake1(X) uTake1(X) (40)
a__uTake2(X1,X2,X3,X4) uTake2(X1,X2,X3,X4) (41)
a__uLength(X1,X2) uLength(X1,X2) (42)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by NaTT @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
a__isNatList#(cons(N,L)) a__and#(a__isNat(N),a__isNatList(L)) (43)
a__and#(tt,T) mark#(T) (44)
mark#(length(X)) a__length#(mark(X)) (45)
mark#(isNatIList(X)) a__isNatIList#(X) (46)
mark#(and(X1,X2)) a__and#(mark(X1),mark(X2)) (47)
a__length#(cons(N,L)) a__isNatList#(L) (48)
a__length#(cons(N,L)) a__isNat#(N) (49)
mark#(uTake2(X1,X2,X3,X4)) mark#(X1) (50)
mark#(and(X1,X2)) mark#(X1) (51)
mark#(and(X1,X2)) mark#(X2) (52)
mark#(isNat(X)) a__isNat#(X) (53)
mark#(take(X1,X2)) mark#(X1) (54)
a__length#(cons(N,L)) a__and#(a__isNat(N),a__isNatList(L)) (55)
a__take#(s(M),cons(N,IL)) a__and#(a__isNat(M),a__and(a__isNat(N),a__isNatIList(IL))) (56)
a__take#(0,IL) a__uTake1#(a__isNatIList(IL)) (57)
mark#(cons(X1,X2)) mark#(X1) (58)
a__isNatIList#(cons(N,IL)) a__isNatIList#(IL) (59)
a__isNatIList#(cons(N,IL)) a__isNat#(N) (60)
a__isNat#(s(N)) a__isNat#(N) (61)
a__take#(s(M),cons(N,IL)) a__uTake2#(a__and(a__isNat(M),a__and(a__isNat(N),a__isNatIList(IL))),M,N,IL) (62)
mark#(uLength(X1,X2)) a__uLength#(mark(X1),X2) (63)
a__take#(s(M),cons(N,IL)) a__isNat#(M) (64)
mark#(length(X)) mark#(X) (65)
a__isNatList#(take(N,IL)) a__and#(a__isNat(N),a__isNatIList(IL)) (66)
mark#(uTake1(X)) mark#(X) (67)
mark#(take(X1,X2)) mark#(X2) (68)
a__length#(cons(N,L)) a__uLength#(a__and(a__isNat(N),a__isNatList(L)),L) (69)
a__take#(0,IL) a__isNatIList#(IL) (70)
a__uLength#(tt,L) a__length#(mark(L)) (71)
mark#(take(X1,X2)) a__take#(mark(X1),mark(X2)) (72)
a__uTake2#(tt,M,N,IL) mark#(N) (73)
a__isNat#(length(L)) a__isNatList#(L) (74)
a__isNatIList#(cons(N,IL)) a__and#(a__isNat(N),a__isNatIList(IL)) (75)
a__uLength#(tt,L) mark#(L) (76)
a__isNatList#(take(N,IL)) a__isNatIList#(IL) (77)
a__take#(s(M),cons(N,IL)) a__isNatIList#(IL) (78)
mark#(uLength(X1,X2)) mark#(X1) (79)
mark#(uTake1(X)) a__uTake1#(mark(X)) (80)
a__isNatList#(take(N,IL)) a__isNat#(N) (81)
mark#(uTake2(X1,X2,X3,X4)) a__uTake2#(mark(X1),X2,X3,X4) (82)
mark#(isNatList(X)) a__isNatList#(X) (83)
a__take#(s(M),cons(N,IL)) a__isNat#(N) (84)
a__isNatList#(cons(N,L)) a__isNat#(N) (85)
a__isNatIList#(IL) a__isNatList#(IL) (86)
mark#(zeros) a__zeros# (87)
a__take#(s(M),cons(N,IL)) a__and#(a__isNat(N),a__isNatIList(IL)) (88)
a__isNatList#(cons(N,L)) a__isNatList#(L) (89)
mark#(s(X)) mark#(X) (90)

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.