Certification Problem

Input (TPDB TRS_Standard/Transformed_CSR_04/ExProp7_Luc06_FR)

The rewrite relation of the following TRS is considered.

f(0) cons(0,n__f(n__s(n__0))) (1)
f(s(0)) f(p(s(0))) (2)
p(s(X)) X (3)
f(X) n__f(X) (4)
s(X) n__s(X) (5)
0 n__0 (6)
activate(n__f(X)) f(activate(X)) (7)
activate(n__s(X)) s(activate(X)) (8)
activate(n__0) 0 (9)
activate(X) X (10)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by NaTT @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
f#(s(0)) p#(s(0)) (11)
activate#(n__s(X)) s#(activate(X)) (12)
activate#(n__s(X)) activate#(X) (13)
activate#(n__f(X)) activate#(X) (14)
activate#(n__0) 0# (15)
f#(s(0)) f#(p(s(0))) (16)
activate#(n__f(X)) f#(activate(X)) (17)

1.1 Dependency Graph Processor

The dependency pairs are split into 2 components.