Certification Problem

Input (TPDB TRS_Standard/Transformed_CSR_04/ExSec11_1_Luc02a_L)

The rewrite relation of the following TRS is considered.

terms(N) cons(recip(sqr(N))) (1)
sqr(0) 0 (2)
sqr(s(X)) s(add(sqr(X),dbl(X))) (3)
dbl(0) 0 (4)
dbl(s(X)) s(s(dbl(X))) (5)
add(0,X) X (6)
add(s(X),Y) s(add(X,Y)) (7)
first(0,X) nil (8)
first(s(X),cons(Y)) cons(Y) (9)
half(0) 0 (10)
half(s(0)) 0 (11)
half(s(s(X))) s(half(X)) (12)
half(dbl(X)) X (13)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by NaTT @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
add#(s(X),Y) add#(X,Y) (14)
sqr#(s(X)) dbl#(X) (15)
terms#(N) sqr#(N) (16)
sqr#(s(X)) sqr#(X) (17)
dbl#(s(X)) dbl#(X) (18)
half#(s(s(X))) half#(X) (19)
sqr#(s(X)) add#(sqr(X),dbl(X)) (20)

1.1 Dependency Graph Processor

The dependency pairs are split into 4 components.