Certification Problem

Input (TPDB TRS_Standard/Applicative_first_order_05/02)

The rewrite relation of the following TRS is considered.

app(app(.,1),x) x (1)
app(app(.,x),1) x (2)
app(app(.,app(i,x)),x) 1 (3)
app(app(.,x),app(i,x)) 1 (4)
app(app(.,app(i,y)),app(app(.,y),z)) z (5)
app(app(.,y),app(app(.,app(i,y)),z)) z (6)
app(i,1) 1 (7)
app(i,app(i,x)) x (8)
app(app(map,f),nil) nil (9)
app(app(map,f),app(app(cons,x),xs)) app(app(cons,app(f,x)),app(app(map,f),xs)) (10)
app(app(filter,f),nil) nil (11)
app(app(filter,f),app(app(cons,x),xs)) app(app(app(app(filter2,app(f,x)),f),x),xs) (12)
app(app(app(app(filter2,true),f),x),xs) app(app(cons,x),app(app(filter,f),xs)) (13)
app(app(app(app(filter2,false),f),x),xs) app(app(filter,f),xs) (14)

Property / Task

Prove or disprove termination.

Answer / Result

Yes.

Proof (by ttt2 @ termCOMP 2023)

1 Dependency Pair Transformation

The following set of initial dependency pairs has been identified.
app#(app(map,f),app(app(cons,x),xs)) app#(app(map,f),xs) (15)
app#(app(map,f),app(app(cons,x),xs)) app#(f,x) (16)
app#(app(map,f),app(app(cons,x),xs)) app#(cons,app(f,x)) (17)
app#(app(map,f),app(app(cons,x),xs)) app#(app(cons,app(f,x)),app(app(map,f),xs)) (18)
app#(app(filter,f),app(app(cons,x),xs)) app#(f,x) (19)
app#(app(filter,f),app(app(cons,x),xs)) app#(filter2,app(f,x)) (20)
app#(app(filter,f),app(app(cons,x),xs)) app#(app(filter2,app(f,x)),f) (21)
app#(app(filter,f),app(app(cons,x),xs)) app#(app(app(filter2,app(f,x)),f),x) (22)
app#(app(filter,f),app(app(cons,x),xs)) app#(app(app(app(filter2,app(f,x)),f),x),xs) (23)
app#(app(app(app(filter2,true),f),x),xs) app#(filter,f) (24)
app#(app(app(app(filter2,true),f),x),xs) app#(app(filter,f),xs) (25)
app#(app(app(app(filter2,true),f),x),xs) app#(cons,x) (26)
app#(app(app(app(filter2,true),f),x),xs) app#(app(cons,x),app(app(filter,f),xs)) (27)
app#(app(app(app(filter2,false),f),x),xs) app#(filter,f) (28)
app#(app(app(app(filter2,false),f),x),xs) app#(app(filter,f),xs) (29)

1.1 Dependency Graph Processor

The dependency pairs are split into 1 component.