Problem: b() -> c() h(h(b(),b()),f(f(h(h(c(),c()),c())))) -> c() f(b()) -> b() f(h(a(),c())) -> a() Proof: Nonconfluence Processor: terms: h(h(c(),b()),f(f(h(h(c(),c()),c())))) *<- h(h(b(),b()),f(f(h(h(c(),c()),c())))) ->* c() Qed