WORST_CASE(?,O(n^3)) * Step 1: MI WORST_CASE(?,O(n^3)) + Considered Problem: - Strict TRS: f(.(.(x,y),z)) -> f(.(x,.(y,z))) f(.(nil(),y)) -> .(nil(),f(y)) f(nil()) -> nil() g(.(x,.(y,z))) -> g(.(.(x,y),z)) g(.(x,nil())) -> .(g(x),nil()) g(nil()) -> nil() - Signature: {f/1,g/1} / {./2,nil/0} - Obligation: innermost runtime complexity wrt. defined symbols {f,g} and constructors {.,nil} + Applied Processor: MI {miKind = Automaton Nothing, miDimension = 3, miUArgs = NoUArgs, miURules = NoURules, miSelector = Nothing} + Details: We apply a matrix interpretation of kind Automaton Nothing: Following symbols are considered usable: all TcT has computed the following interpretation: p(.) = [1 0 0] [1 0 0] [1] [0 1 0] x_1 + [1 0 0] x_2 + [0] [1 0 0] [0 0 1] [0] p(f) = [2 0 1] [0] [2 0 1] x_1 + [0] [0 0 1] [1] p(g) = [2 1 0] [1] [3 0 0] x_1 + [0] [0 2 2] [0] p(nil) = [1] [2] [1] Following rules are strictly oriented: f(.(.(x,y),z)) = [3 0 0] [3 0 0] [2 0 1] [5] [3 0 0] x + [3 0 0] y + [2 0 1] z + [5] [1 0 0] [1 0 0] [0 0 1] [2] > [3 0 0] [3 0 0] [2 0 1] [4] [3 0 0] x + [3 0 0] y + [2 0 1] z + [4] [1 0 0] [1 0 0] [0 0 1] [1] = f(.(x,.(y,z))) f(.(nil(),y)) = [2 0 1] [5] [2 0 1] y + [5] [0 0 1] [2] > [2 0 1] [2] [2 0 1] y + [2] [0 0 1] [2] = .(nil(),f(y)) f(nil()) = [3] [3] [2] > [1] [2] [1] = nil() g(.(x,.(y,z))) = [2 1 0] [3 0 0] [3 0 0] [6] [3 0 0] x + [3 0 0] y + [3 0 0] z + [6] [2 2 0] [4 0 0] [2 0 2] [2] > [2 1 0] [3 0 0] [3 0 0] [5] [3 0 0] x + [3 0 0] y + [3 0 0] z + [6] [2 2 0] [4 0 0] [2 0 2] [2] = g(.(.(x,y),z)) g(.(x,nil())) = [2 1 0] [6] [3 0 0] x + [6] [2 2 0] [4] > [2 1 0] [3] [3 0 0] x + [1] [2 1 0] [2] = .(g(x),nil()) g(nil()) = [5] [3] [6] > [1] [2] [1] = nil() Following rules are (at-least) weakly oriented: WORST_CASE(?,O(n^3))