WORST_CASE(?,O(n^3)) * Step 1: MI WORST_CASE(?,O(n^3)) + Considered Problem: - Strict TRS: active(c()) -> mark(d()) active(g(X)) -> mark(h(X)) active(h(d())) -> mark(g(c())) g(ok(X)) -> ok(g(X)) h(ok(X)) -> ok(h(X)) proper(c()) -> ok(c()) proper(d()) -> ok(d()) proper(g(X)) -> g(proper(X)) proper(h(X)) -> h(proper(X)) top(mark(X)) -> top(proper(X)) top(ok(X)) -> top(active(X)) - Signature: {active/1,g/1,h/1,proper/1,top/1} / {c/0,d/0,mark/1,ok/1} - Obligation: innermost runtime complexity wrt. defined symbols {active,g,h,proper,top} and constructors {c,d,mark,ok} + Applied Processor: MI {miKind = Automaton Nothing, miDimension = 3, miUArgs = NoUArgs, miURules = NoURules, miSelector = Nothing} + Details: We apply a matrix interpretation of kind Automaton Nothing: Following symbols are considered usable: all TcT has computed the following interpretation: p(active) = [1 0 1] [0] [1 1 0] x_1 + [0] [1 0 0] [1] p(c) = [0] [7] [1] p(d) = [0] [1] [5] p(g) = [2 0 0] [0] [0 0 5] x_1 + [4] [0 0 2] [3] p(h) = [2 0 0] [0] [0 0 3] x_1 + [0] [0 0 2] [3] p(mark) = [1 0 0] [0] [1 1 1] x_1 + [1] [1 0 0] [1] p(ok) = [1 0 0] [2] [1 1 0] x_1 + [0] [1 0 1] [0] p(proper) = [4 0 1] [2] [0 1 0] x_1 + [0] [0 0 1] [0] p(top) = [2 4 2] [0] [2 5 3] x_1 + [4] [1 4 2] [0] Following rules are strictly oriented: active(c()) = [1] [7] [1] > [0] [7] [1] = mark(d()) active(g(X)) = [2 0 2] [3] [2 0 5] X + [4] [2 0 0] [1] > [2 0 0] [0] [2 0 5] X + [4] [2 0 0] [1] = mark(h(X)) active(h(d())) = [13] [15] [1] > [0] [15] [1] = mark(g(c())) g(ok(X)) = [2 0 0] [4] [5 0 5] X + [4] [2 0 2] [3] > [2 0 0] [2] [2 0 5] X + [4] [2 0 2] [3] = ok(g(X)) h(ok(X)) = [2 0 0] [4] [3 0 3] X + [0] [2 0 2] [3] > [2 0 0] [2] [2 0 3] X + [0] [2 0 2] [3] = ok(h(X)) proper(c()) = [3] [7] [1] > [2] [7] [1] = ok(c()) proper(d()) = [7] [1] [5] > [2] [1] [5] = ok(d()) proper(g(X)) = [8 0 2] [5] [0 0 5] X + [4] [0 0 2] [3] > [8 0 2] [4] [0 0 5] X + [4] [0 0 2] [3] = g(proper(X)) proper(h(X)) = [8 0 2] [5] [0 0 3] X + [0] [0 0 2] [3] > [8 0 2] [4] [0 0 3] X + [0] [0 0 2] [3] = h(proper(X)) top(mark(X)) = [ 8 4 4] [6] [10 5 5] X + [12] [ 7 4 4] [6] > [8 4 4] [4] [8 5 5] X + [8] [4 4 3] [2] = top(proper(X)) top(ok(X)) = [ 8 4 2] [4] [10 5 3] X + [8] [ 7 4 2] [2] > [ 8 4 2] [2] [10 5 2] X + [7] [ 7 4 1] [2] = top(active(X)) Following rules are (at-least) weakly oriented: WORST_CASE(?,O(n^3))