WORST_CASE(?,O(n^1))
* Step 1: Bounds WORST_CASE(?,O(n^1))
    + Considered Problem:
        - Strict TRS:
            add0(0(),x2) -> x2
            add0(S(x),x2) -> +(S(0()),add0(x2,x))
        - Weak TRS:
            +(x,S(0())) -> S(x)
            +(S(0()),y) -> S(y)
        - Signature:
            {+/2,add0/2} / {0/0,S/1}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {+,add0} and constructors {0,S}
    + Applied Processor:
        Bounds {initialAutomaton = perSymbol, enrichment = match}
    + Details:
        The problem is match-bounded by 1.
        The enriched problem is compatible with follwoing automaton.
          +_0(2,2) -> 1
          +_0(2,3) -> 1
          +_0(3,2) -> 1
          +_0(3,3) -> 1
          +_1(5,6) -> 4
          +_1(5,6) -> 6
          0_0() -> 2
          0_0() -> 4
          0_0() -> 6
          0_1() -> 7
          S_0(2) -> 1
          S_0(2) -> 3
          S_0(2) -> 4
          S_0(2) -> 6
          S_0(3) -> 1
          S_0(3) -> 3
          S_0(3) -> 4
          S_0(3) -> 6
          S_1(5) -> 4
          S_1(5) -> 6
          S_1(6) -> 4
          S_1(6) -> 6
          S_1(7) -> 5
          add0_0(2,2) -> 4
          add0_0(2,3) -> 4
          add0_0(3,2) -> 4
          add0_0(3,3) -> 4
          add0_1(2,2) -> 6
          add0_1(2,3) -> 6
          add0_1(3,2) -> 6
          add0_1(3,3) -> 6
          2 -> 4
          2 -> 6
          3 -> 4
          3 -> 6
* Step 2: EmptyProcessor WORST_CASE(?,O(1))
    + Considered Problem:
        - Weak TRS:
            +(x,S(0())) -> S(x)
            +(S(0()),y) -> S(y)
            add0(0(),x2) -> x2
            add0(S(x),x2) -> +(S(0()),add0(x2,x))
        - Signature:
            {+/2,add0/2} / {0/0,S/1}
        - Obligation:
            innermost runtime complexity wrt. defined symbols {+,add0} and constructors {0,S}
    + Applied Processor:
        EmptyProcessor
    + Details:
        The problem is already closed. The intended complexity is O(1).

WORST_CASE(?,O(n^1))