interpretations
TIMEOUT
We are left with following problem, upon which TcT provides the
certificate TIMEOUT.
Strict Trs:
{ p(0()) -> 0()
, p(s(X)) -> X
, leq(0(), Y) -> true()
, leq(s(X), 0()) -> false()
, leq(s(X), s(Y)) -> leq(X, Y)
, if(true(), X, Y) -> X
, if(false(), X, Y) -> Y
, diff(X, Y) -> if(leq(X, Y), 0(), s(diff(p(X), Y))) }
Obligation:
innermost runtime complexity
Answer:
TIMEOUT
Computation stopped due to timeout after 20.0 seconds.
Arrrr..
lmpo
MAYBE
We are left with following problem, upon which TcT provides the
certificate MAYBE.
Strict Trs:
{ p(0()) -> 0()
, p(s(X)) -> X
, leq(0(), Y) -> true()
, leq(s(X), 0()) -> false()
, leq(s(X), s(Y)) -> leq(X, Y)
, if(true(), X, Y) -> X
, if(false(), X, Y) -> Y
, diff(X, Y) -> if(leq(X, Y), 0(), s(diff(p(X), Y))) }
Obligation:
innermost runtime complexity
Answer:
MAYBE
The input cannot be shown compatible
Arrrr..
mpo
MAYBE
We are left with following problem, upon which TcT provides the
certificate MAYBE.
Strict Trs:
{ p(0()) -> 0()
, p(s(X)) -> X
, leq(0(), Y) -> true()
, leq(s(X), 0()) -> false()
, leq(s(X), s(Y)) -> leq(X, Y)
, if(true(), X, Y) -> X
, if(false(), X, Y) -> Y
, diff(X, Y) -> if(leq(X, Y), 0(), s(diff(p(X), Y))) }
Obligation:
innermost runtime complexity
Answer:
MAYBE
The input cannot be shown compatible
Arrrr..
popstar
MAYBE
We are left with following problem, upon which TcT provides the
certificate MAYBE.
Strict Trs:
{ p(0()) -> 0()
, p(s(X)) -> X
, leq(0(), Y) -> true()
, leq(s(X), 0()) -> false()
, leq(s(X), s(Y)) -> leq(X, Y)
, if(true(), X, Y) -> X
, if(false(), X, Y) -> Y
, diff(X, Y) -> if(leq(X, Y), 0(), s(diff(p(X), Y))) }
Obligation:
innermost runtime complexity
Answer:
MAYBE
The input cannot be shown compatible
Arrrr..
popstar-ps
MAYBE
We are left with following problem, upon which TcT provides the
certificate MAYBE.
Strict Trs:
{ p(0()) -> 0()
, p(s(X)) -> X
, leq(0(), Y) -> true()
, leq(s(X), 0()) -> false()
, leq(s(X), s(Y)) -> leq(X, Y)
, if(true(), X, Y) -> X
, if(false(), X, Y) -> Y
, diff(X, Y) -> if(leq(X, Y), 0(), s(diff(p(X), Y))) }
Obligation:
innermost runtime complexity
Answer:
MAYBE
The input cannot be shown compatible
Arrrr..