Tool CaT
stdout:
MAYBE
Problem:
p(0()) -> 0()
p(s(x)) -> x
minus(x,0()) -> x
minus(s(x),s(y)) -> minus(x,y)
minus(x,s(y)) -> p(minus(x,y))
div(0(),s(y)) -> 0()
div(s(x),s(y)) -> s(div(minus(s(x),s(y)),s(y)))
log(s(0()),s(s(y))) -> 0()
log(s(s(x)),s(s(y))) -> s(log(div(minus(x,y),s(s(y))),s(s(y))))
Proof:
OpenTool IRC1
stdout:
MAYBE
Tool IRC2
stdout:
TIMEOUT
'Fastest (timeout of 60.0 seconds)'
-----------------------------------
Answer: TIMEOUT
Input Problem: innermost runtime-complexity with respect to
Rules:
{ p(0()) -> 0()
, p(s(x)) -> x
, minus(x, 0()) -> x
, minus(s(x), s(y)) -> minus(x, y)
, minus(x, s(y)) -> p(minus(x, y))
, div(0(), s(y)) -> 0()
, div(s(x), s(y)) -> s(div(minus(s(x), s(y)), s(y)))
, log(s(0()), s(s(y))) -> 0()
, log(s(s(x)), s(s(y))) ->
s(log(div(minus(x, y), s(s(y))), s(s(y))))}
Proof Output:
Computation stopped due to timeout after 60.0 secondsTool RC1
stdout:
MAYBE
Tool RC2
stdout:
TIMEOUT
'Fastest (timeout of 60.0 seconds)'
-----------------------------------
Answer: TIMEOUT
Input Problem: runtime-complexity with respect to
Rules:
{ p(0()) -> 0()
, p(s(x)) -> x
, minus(x, 0()) -> x
, minus(s(x), s(y)) -> minus(x, y)
, minus(x, s(y)) -> p(minus(x, y))
, div(0(), s(y)) -> 0()
, div(s(x), s(y)) -> s(div(minus(s(x), s(y)), s(y)))
, log(s(0()), s(s(y))) -> 0()
, log(s(s(x)), s(s(y))) ->
s(log(div(minus(x, y), s(s(y))), s(s(y))))}
Proof Output:
Computation stopped due to timeout after 60.0 seconds