Tool CaT
Execution Time | Unknown |
---|
Answer | MAYBE |
---|
Input | SK90 2.30 |
---|
stdout:
MAYBE
Problem:
not(x) -> xor(x,true())
implies(x,y) -> xor(and(x,y),xor(x,true()))
or(x,y) -> xor(and(x,y),xor(x,y))
=(x,y) -> xor(x,xor(y,true()))
Proof:
OpenTool IRC1
Execution Time | Unknown |
---|
Answer | YES(?,O(1)) |
---|
Input | SK90 2.30 |
---|
stdout:
YES(?,O(1))
Tool IRC2
Execution Time | Unknown |
---|
Answer | YES(?,O(1)) |
---|
Input | SK90 2.30 |
---|
stdout:
YES(?,O(1))
'Fastest (timeout of 60.0 seconds)'
-----------------------------------
Answer: YES(?,O(1))
Input Problem: innermost runtime-complexity with respect to
Rules:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
Proof Output:
'wdg' proved the best result:
Details:
--------
'wdg' succeeded with the following output:
'wdg'
-----
Answer: YES(?,O(1))
Input Problem: innermost runtime-complexity with respect to
Rules:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
Proof Output:
Transformation Details:
-----------------------
We have computed the following set of weak (innermost) dependency pairs:
{ 1: not^#(x) -> c_0()
, 2: implies^#(x, y) -> c_1()
, 3: or^#(x, y) -> c_2()
, 4: =^#(x, y) -> c_3()}
The dependency graph contains no edges and the usable rules are empty.
Tool RC1
Execution Time | Unknown |
---|
Answer | YES(?,O(1)) |
---|
Input | SK90 2.30 |
---|
stdout:
YES(?,O(1))
Tool RC2
Execution Time | Unknown |
---|
Answer | YES(?,O(1)) |
---|
Input | SK90 2.30 |
---|
stdout:
YES(?,O(1))
'Fastest (timeout of 60.0 seconds)'
-----------------------------------
Answer: YES(?,O(1))
Input Problem: runtime-complexity with respect to
Rules:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
Proof Output:
'wdg' proved the best result:
Details:
--------
'wdg' succeeded with the following output:
'wdg'
-----
Answer: YES(?,O(1))
Input Problem: runtime-complexity with respect to
Rules:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
Proof Output:
Transformation Details:
-----------------------
We have computed the following set of weak (innermost) dependency pairs:
{ 1: not^#(x) -> c_0(x)
, 2: implies^#(x, y) -> c_1(x, y, x)
, 3: or^#(x, y) -> c_2(x, y, x, y)
, 4: =^#(x, y) -> c_3(x, y)}
The dependency graph contains no edges and the usable rules are empty.
Tool pair1rc
Execution Time | Unknown |
---|
Answer | YES(?,O(n^1)) |
---|
Input | SK90 2.30 |
---|
stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: none
Certificate: YES(?,O(n^1))
Application of 'pair1 (timeout of 60.0 seconds)':
-------------------------------------------------
The processor is not applicable, reason is:
Input problem is not restricted to innermost rewriting
We abort the transformation and continue with the subprocessor on the problem
Strict Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: none
1) 'Fastest' proved the goal fastest:
'Sequentially' proved the goal fastest:
'Fastest' succeeded:
'matrix-interpretation of dimension 2 (timeout of 100.0 seconds)' proved the goal fastest:
The following argument positions are usable:
Uargs(not) = {}, Uargs(xor) = {}, Uargs(implies) = {},
Uargs(and) = {}, Uargs(or) = {}, Uargs(=) = {}
We have the following constructor-restricted (at most 1 in the main diagonals) matrix interpretation:
Interpretation Functions:
not(x1) = [2 2] x1 + [2]
[2 1] [2]
xor(x1, x2) = [0 0] x1 + [0 0] x2 + [1]
[0 0] [0 0] [1]
true() = [1]
[1]
implies(x1, x2) = [2 2] x1 + [2 2] x2 + [2]
[1 2] [1 2] [2]
and(x1, x2) = [1 2] x1 + [1 1] x2 + [1]
[0 0] [0 0] [1]
or(x1, x2) = [2 2] x1 + [2 2] x2 + [2]
[1 2] [1 2] [2]
=(x1, x2) = [2 2] x1 + [1 2] x2 + [2]
[1 2] [1 1] [1]
Hurray, we answered YES(?,O(n^1))Tool pair2rc
Execution Time | Unknown |
---|
Answer | YES(?,O(n^1)) |
---|
Input | SK90 2.30 |
---|
stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: none
Certificate: YES(?,O(n^1))
Application of 'pair2 (timeout of 60.0 seconds)':
-------------------------------------------------
The processor is not applicable, reason is:
Input problem is not restricted to innermost rewriting
We abort the transformation and continue with the subprocessor on the problem
Strict Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: none
1) 'Fastest' proved the goal fastest:
'Sequentially' proved the goal fastest:
'Fastest' succeeded:
'matrix-interpretation of dimension 2 (timeout of 100.0 seconds)' proved the goal fastest:
The following argument positions are usable:
Uargs(not) = {}, Uargs(xor) = {}, Uargs(implies) = {},
Uargs(and) = {}, Uargs(or) = {}, Uargs(=) = {}
We have the following constructor-restricted (at most 1 in the main diagonals) matrix interpretation:
Interpretation Functions:
not(x1) = [2 2] x1 + [2]
[2 1] [2]
xor(x1, x2) = [0 0] x1 + [0 0] x2 + [1]
[0 0] [0 0] [1]
true() = [1]
[1]
implies(x1, x2) = [2 2] x1 + [2 2] x2 + [2]
[1 2] [1 2] [2]
and(x1, x2) = [1 2] x1 + [1 1] x2 + [1]
[0 0] [0 0] [1]
or(x1, x2) = [2 2] x1 + [2 2] x2 + [2]
[1 2] [1 2] [2]
=(x1, x2) = [2 2] x1 + [1 2] x2 + [2]
[1 2] [1 1] [1]
Hurray, we answered YES(?,O(n^1))Tool pair3irc
Execution Time | Unknown |
---|
Answer | YES(?,O(n^1)) |
---|
Input | SK90 2.30 |
---|
stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: innermost
Certificate: YES(?,O(n^1))
Application of 'pair3 (timeout of 60.0 seconds)':
-------------------------------------------------
The input problem contains no overlaps that give rise to inapplicable rules.
We abort the transformation and continue with the subprocessor on the problem
Strict Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: innermost
1) 'Fastest' proved the goal fastest:
'Sequentially' proved the goal fastest:
'Fastest' succeeded:
'matrix-interpretation of dimension 2 (timeout of 100.0 seconds)' proved the goal fastest:
The following argument positions are usable:
Uargs(not) = {}, Uargs(xor) = {}, Uargs(implies) = {},
Uargs(and) = {}, Uargs(or) = {}, Uargs(=) = {}
We have the following constructor-restricted (at most 1 in the main diagonals) matrix interpretation:
Interpretation Functions:
not(x1) = [2 2] x1 + [2]
[2 1] [2]
xor(x1, x2) = [0 0] x1 + [0 0] x2 + [1]
[0 0] [0 0] [1]
true() = [1]
[1]
implies(x1, x2) = [2 2] x1 + [2 2] x2 + [2]
[1 2] [1 2] [2]
and(x1, x2) = [1 2] x1 + [1 1] x2 + [1]
[0 0] [0 0] [1]
or(x1, x2) = [2 2] x1 + [2 2] x2 + [2]
[1 2] [1 2] [2]
=(x1, x2) = [2 2] x1 + [1 2] x2 + [2]
[1 2] [1 1] [1]
Hurray, we answered YES(?,O(n^1))Tool pair3rc
Execution Time | Unknown |
---|
Answer | YES(?,O(n^1)) |
---|
Input | SK90 2.30 |
---|
stdout:
YES(?,O(n^1))
We consider the following Problem:
Strict Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: none
Certificate: YES(?,O(n^1))
Application of 'pair3 (timeout of 60.0 seconds)':
-------------------------------------------------
The processor is not applicable, reason is:
Input problem is not restricted to innermost rewriting
We abort the transformation and continue with the subprocessor on the problem
Strict Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: none
1) 'Fastest' proved the goal fastest:
'Sequentially' proved the goal fastest:
'Fastest' succeeded:
'matrix-interpretation of dimension 2 (timeout of 100.0 seconds)' proved the goal fastest:
The following argument positions are usable:
Uargs(not) = {}, Uargs(xor) = {}, Uargs(implies) = {},
Uargs(and) = {}, Uargs(or) = {}, Uargs(=) = {}
We have the following constructor-restricted (at most 1 in the main diagonals) matrix interpretation:
Interpretation Functions:
not(x1) = [2 2] x1 + [2]
[2 1] [2]
xor(x1, x2) = [0 0] x1 + [0 0] x2 + [1]
[0 0] [0 0] [1]
true() = [1]
[1]
implies(x1, x2) = [2 2] x1 + [2 2] x2 + [2]
[1 2] [1 2] [2]
and(x1, x2) = [1 2] x1 + [1 1] x2 + [1]
[0 0] [0 0] [1]
or(x1, x2) = [2 2] x1 + [2 2] x2 + [2]
[1 2] [1 2] [2]
=(x1, x2) = [2 2] x1 + [1 2] x2 + [2]
[1 2] [1 1] [1]
Hurray, we answered YES(?,O(n^1))Tool rc
Execution Time | Unknown |
---|
Answer | YES(O(1),O(1)) |
---|
Input | SK90 2.30 |
---|
stdout:
YES(O(1),O(1))
We consider the following Problem:
Strict Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: none
Certificate: YES(O(1),O(1))
Application of 'rc (timeout of 60.0 seconds)':
----------------------------------------------
'dp' proved the goal fastest:
We have computed the following dependency pairs
Strict Dependency Pairs:
{ not^#(x) -> c_1(x)
, implies^#(x, y) -> c_2(x, y, x)
, or^#(x, y) -> c_3(x, y, x, y)
, =^#(x, y) -> c_4(x, y)}
We consider the following Problem:
Strict DPs:
{ not^#(x) -> c_1(x)
, implies^#(x, y) -> c_2(x, y, x)
, or^#(x, y) -> c_3(x, y, x, y)
, =^#(x, y) -> c_4(x, y)}
Strict Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: none
Certificate: YES(O(1),O(1))
Application of 'usablerules':
-----------------------------
No rule is usable.
We consider the following Problem:
Strict DPs:
{ not^#(x) -> c_1(x)
, implies^#(x, y) -> c_2(x, y, x)
, or^#(x, y) -> c_3(x, y, x, y)
, =^#(x, y) -> c_4(x, y)}
StartTerms: basic terms
Strategy: none
Certificate: YES(O(1),O(1))
Application of 'Fastest':
-------------------------
'removetails >>> ... >>> ... >>> ...' proved the goal fastest:
We consider the the dependency-graph
1: not^#(x) -> c_1(x)
2: implies^#(x, y) -> c_2(x, y, x)
3: or^#(x, y) -> c_3(x, y, x, y)
4: =^#(x, y) -> c_4(x, y)
together with the congruence-graph
->{1} Noncyclic, trivial, SCC
->{2} Noncyclic, trivial, SCC
->{3} Noncyclic, trivial, SCC
->{4} Noncyclic, trivial, SCC
Here rules are as follows:
{ 1: not^#(x) -> c_1(x)
, 2: implies^#(x, y) -> c_2(x, y, x)
, 3: or^#(x, y) -> c_3(x, y, x, y)
, 4: =^#(x, y) -> c_4(x, y)}
The following rules are either leafs or part of trailing weak paths, and thus they can be removed:
{ 4: =^#(x, y) -> c_4(x, y)
, 3: or^#(x, y) -> c_3(x, y, x, y)
, 2: implies^#(x, y) -> c_2(x, y, x)
, 1: not^#(x) -> c_1(x)}
We consider the following Problem:
StartTerms: basic terms
Strategy: none
Certificate: YES(O(1),O(1))
Application of 'simpDPRHS >>> ...':
-----------------------------------
No rule was simplified
We apply the transformation 'usablerules' on the resulting sub-problems:
Sub-problem 1:
--------------
We consider the problem
StartTerms: basic terms
Strategy: none
The input problem is not a DP-problem.
We abort the transformation and continue with the subprocessor on the problem
StartTerms: basic terms
Strategy: none
1) We fail transforming the problem using 'weightgap of dimension Nat 2, maximal degree 1, cbits 4'
All strict components are empty, nothing to further orient
We try instead 'weightgap of dimension Nat 3, maximal degree 3, cbits 4 <> ...' on the problem
StartTerms: basic terms
Strategy: none
We fail transforming the problem using 'weightgap of dimension Nat 3, maximal degree 3, cbits 4'
All strict components are empty, nothing to further orient
We try instead 'weightgap of dimension Nat 4, maximal degree 3, cbits 4' on the problem
StartTerms: basic terms
Strategy: none
All strict components are empty, nothing to further orient
We abort the transformation and continue with the subprocessor on the problem
StartTerms: basic terms
Strategy: none
1) No dependency-pair could be removed
We apply the transformation 'weightgap of dimension Nat 2, maximal degree 1, cbits 4 <> ...' on the resulting sub-problems:
Sub-problem 1:
--------------
We consider the problem
StartTerms: basic terms
Strategy: none
We fail transforming the problem using 'weightgap of dimension Nat 2, maximal degree 1, cbits 4'
All strict components are empty, nothing to further orient
We try instead 'weightgap of dimension Nat 3, maximal degree 3, cbits 4 <> ...' on the problem
StartTerms: basic terms
Strategy: none
We fail transforming the problem using 'weightgap of dimension Nat 3, maximal degree 3, cbits 4'
All strict components are empty, nothing to further orient
We try instead 'weightgap of dimension Nat 4, maximal degree 3, cbits 4' on the problem
StartTerms: basic terms
Strategy: none
All strict components are empty, nothing to further orient
We abort the transformation and continue with the subprocessor on the problem
StartTerms: basic terms
Strategy: none
1) 'Sequentially' proved the goal fastest:
'empty' succeeded:
Empty rules are trivially bounded
Hurray, we answered YES(O(1),O(1))Tool tup3irc
Execution Time | 6.1435938e-2ms |
---|
Answer | YES(O(1),O(1)) |
---|
Input | SK90 2.30 |
---|
stdout:
YES(O(1),O(1))
We consider the following Problem:
Strict Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: innermost
Certificate: YES(O(1),O(1))
Application of 'tup3 (timeout of 60.0 seconds)':
------------------------------------------------
The input problem contains no overlaps that give rise to inapplicable rules.
We abort the transformation and continue with the subprocessor on the problem
Strict Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: innermost
1) 'dp' proved the goal fastest:
We have computed the following dependency pairs
Strict Dependency Pairs:
{ not^#(x) -> c_1()
, implies^#(x, y) -> c_2()
, or^#(x, y) -> c_3()
, =^#(x, y) -> c_4()}
We consider the following Problem:
Strict DPs:
{ not^#(x) -> c_1()
, implies^#(x, y) -> c_2()
, or^#(x, y) -> c_3()
, =^#(x, y) -> c_4()}
Weak Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: innermost
Certificate: YES(O(1),O(1))
Application of 'Fastest':
-------------------------
'compose (statically using 'split all congruence from CWD except leafs', multiplication)' proved the goal fastest:
Compose is inapplicable since some weak rule is size increasing
We abort the transformation and continue with the subprocessor on the problem
Strict DPs:
{ not^#(x) -> c_1()
, implies^#(x, y) -> c_2()
, or^#(x, y) -> c_3()
, =^#(x, y) -> c_4()}
Weak Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: innermost
1) We consider the the dependency-graph
1: not^#(x) -> c_1()
2: implies^#(x, y) -> c_2()
3: or^#(x, y) -> c_3()
4: =^#(x, y) -> c_4()
together with the congruence-graph
->{1} Noncyclic, trivial, SCC
->{2} Noncyclic, trivial, SCC
->{3} Noncyclic, trivial, SCC
->{4} Noncyclic, trivial, SCC
Here rules are as follows:
{ 1: not^#(x) -> c_1()
, 2: implies^#(x, y) -> c_2()
, 3: or^#(x, y) -> c_3()
, 4: =^#(x, y) -> c_4()}
The following rules are either leafs or part of trailing weak paths, and thus they can be removed:
{ 4: =^#(x, y) -> c_4()
, 3: or^#(x, y) -> c_3()
, 2: implies^#(x, y) -> c_2()
, 1: not^#(x) -> c_1()}
We consider the following Problem:
Weak Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: innermost
Certificate: YES(O(1),O(1))
Application of 'simpDPRHS >>> ...':
-----------------------------------
No rule was simplified
We apply the transformation 'usablerules' on the resulting sub-problems:
Sub-problem 1:
--------------
We consider the problem
Weak Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: innermost
The input problem is not a DP-problem.
We abort the transformation and continue with the subprocessor on the problem
Weak Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: innermost
1) We fail transforming the problem using 'weightgap of dimension Nat 2, maximal degree 1, cbits 4'
All strict components are empty, nothing to further orient
We try instead 'weightgap of dimension Nat 3, maximal degree 3, cbits 4 <> ...' on the problem
Weak Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: innermost
We fail transforming the problem using 'weightgap of dimension Nat 3, maximal degree 3, cbits 4'
All strict components are empty, nothing to further orient
We try instead 'weightgap of dimension Nat 4, maximal degree 3, cbits 4' on the problem
Weak Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: innermost
All strict components are empty, nothing to further orient
We abort the transformation and continue with the subprocessor on the problem
Weak Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: innermost
1) No dependency-pair could be removed
We apply the transformation 'weightgap of dimension Nat 2, maximal degree 1, cbits 4 <> ...' on the resulting sub-problems:
Sub-problem 1:
--------------
We consider the problem
Weak Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: innermost
We fail transforming the problem using 'weightgap of dimension Nat 2, maximal degree 1, cbits 4'
All strict components are empty, nothing to further orient
We try instead 'weightgap of dimension Nat 3, maximal degree 3, cbits 4 <> ...' on the problem
Weak Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: innermost
We fail transforming the problem using 'weightgap of dimension Nat 3, maximal degree 3, cbits 4'
All strict components are empty, nothing to further orient
We try instead 'weightgap of dimension Nat 4, maximal degree 3, cbits 4' on the problem
Weak Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: innermost
All strict components are empty, nothing to further orient
We abort the transformation and continue with the subprocessor on the problem
Weak Trs:
{ not(x) -> xor(x, true())
, implies(x, y) -> xor(and(x, y), xor(x, true()))
, or(x, y) -> xor(and(x, y), xor(x, y))
, =(x, y) -> xor(x, xor(y, true()))}
StartTerms: basic terms
Strategy: innermost
1) 'empty' succeeded:
Empty rules are trivially bounded
Hurray, we answered YES(O(1),O(1))