Tool CaT
stdout:
MAYBE
Problem:
-(x,0()) -> x
-(s(x),s(y)) -> -(x,y)
min(x,0()) -> 0()
min(0(),y) -> 0()
min(s(x),s(y)) -> s(min(x,y))
twice(0()) -> 0()
twice(s(x)) -> s(s(twice(x)))
f(s(x),s(y)) -> f(-(y,min(x,y)),s(twice(min(x,y))))
f(s(x),s(y)) -> f(-(x,min(x,y)),s(twice(min(x,y))))
Proof:
OpenTool IRC1
stdout:
MAYBE
Tool IRC2
stdout:
TIMEOUT
'Fastest (timeout of 60.0 seconds)'
-----------------------------------
Answer: TIMEOUT
Input Problem: innermost runtime-complexity with respect to
Rules:
{ -(x, 0()) -> x
, -(s(x), s(y)) -> -(x, y)
, min(x, 0()) -> 0()
, min(0(), y) -> 0()
, min(s(x), s(y)) -> s(min(x, y))
, twice(0()) -> 0()
, twice(s(x)) -> s(s(twice(x)))
, f(s(x), s(y)) -> f(-(y, min(x, y)), s(twice(min(x, y))))
, f(s(x), s(y)) -> f(-(x, min(x, y)), s(twice(min(x, y))))}
Proof Output:
Computation stopped due to timeout after 60.0 secondsTool RC1
stdout:
MAYBE
Tool RC2
stdout:
TIMEOUT
'Fastest (timeout of 60.0 seconds)'
-----------------------------------
Answer: TIMEOUT
Input Problem: runtime-complexity with respect to
Rules:
{ -(x, 0()) -> x
, -(s(x), s(y)) -> -(x, y)
, min(x, 0()) -> 0()
, min(0(), y) -> 0()
, min(s(x), s(y)) -> s(min(x, y))
, twice(0()) -> 0()
, twice(s(x)) -> s(s(twice(x)))
, f(s(x), s(y)) -> f(-(y, min(x, y)), s(twice(min(x, y))))
, f(s(x), s(y)) -> f(-(x, min(x, y)), s(twice(min(x, y))))}
Proof Output:
Computation stopped due to timeout after 60.0 seconds