MAYBE We are left with following problem, upon which TcT provides the certificate MAYBE. Strict Trs: { leq(0(), y) -> true() , leq(s(x), 0()) -> false() , leq(s(x), s(y)) -> leq(x, y) , if(true(), x, y) -> x , if(false(), x, y) -> y , -(x, 0()) -> x , -(s(x), s(y)) -> -(x, y) , mod(0(), y) -> 0() , mod(s(x), 0()) -> 0() , mod(s(x), s(y)) -> if(leq(y, x), mod(-(s(x), s(y)), s(y)), s(x)) } Obligation: innermost runtime complexity Answer: MAYBE We add following dependency tuples: Strict DPs: { leq^#(0(), y) -> c_1() , leq^#(s(x), 0()) -> c_2() , leq^#(s(x), s(y)) -> c_3(leq^#(x, y)) , if^#(true(), x, y) -> c_4() , if^#(false(), x, y) -> c_5() , -^#(x, 0()) -> c_6() , -^#(s(x), s(y)) -> c_7(-^#(x, y)) , mod^#(0(), y) -> c_8() , mod^#(s(x), 0()) -> c_9() , mod^#(s(x), s(y)) -> c_10(if^#(leq(y, x), mod(-(s(x), s(y)), s(y)), s(x)), leq^#(y, x), mod^#(-(s(x), s(y)), s(y)), -^#(s(x), s(y))) } and mark the set of starting terms. We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { leq^#(0(), y) -> c_1() , leq^#(s(x), 0()) -> c_2() , leq^#(s(x), s(y)) -> c_3(leq^#(x, y)) , if^#(true(), x, y) -> c_4() , if^#(false(), x, y) -> c_5() , -^#(x, 0()) -> c_6() , -^#(s(x), s(y)) -> c_7(-^#(x, y)) , mod^#(0(), y) -> c_8() , mod^#(s(x), 0()) -> c_9() , mod^#(s(x), s(y)) -> c_10(if^#(leq(y, x), mod(-(s(x), s(y)), s(y)), s(x)), leq^#(y, x), mod^#(-(s(x), s(y)), s(y)), -^#(s(x), s(y))) } Weak Trs: { leq(0(), y) -> true() , leq(s(x), 0()) -> false() , leq(s(x), s(y)) -> leq(x, y) , if(true(), x, y) -> x , if(false(), x, y) -> y , -(x, 0()) -> x , -(s(x), s(y)) -> -(x, y) , mod(0(), y) -> 0() , mod(s(x), 0()) -> 0() , mod(s(x), s(y)) -> if(leq(y, x), mod(-(s(x), s(y)), s(y)), s(x)) } Obligation: innermost runtime complexity Answer: MAYBE We estimate the number of application of {1,2,4,5,6,8,9} by applications of Pre({1,2,4,5,6,8,9}) = {3,7,10}. Here rules are labeled as follows: DPs: { 1: leq^#(0(), y) -> c_1() , 2: leq^#(s(x), 0()) -> c_2() , 3: leq^#(s(x), s(y)) -> c_3(leq^#(x, y)) , 4: if^#(true(), x, y) -> c_4() , 5: if^#(false(), x, y) -> c_5() , 6: -^#(x, 0()) -> c_6() , 7: -^#(s(x), s(y)) -> c_7(-^#(x, y)) , 8: mod^#(0(), y) -> c_8() , 9: mod^#(s(x), 0()) -> c_9() , 10: mod^#(s(x), s(y)) -> c_10(if^#(leq(y, x), mod(-(s(x), s(y)), s(y)), s(x)), leq^#(y, x), mod^#(-(s(x), s(y)), s(y)), -^#(s(x), s(y))) } We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { leq^#(s(x), s(y)) -> c_3(leq^#(x, y)) , -^#(s(x), s(y)) -> c_7(-^#(x, y)) , mod^#(s(x), s(y)) -> c_10(if^#(leq(y, x), mod(-(s(x), s(y)), s(y)), s(x)), leq^#(y, x), mod^#(-(s(x), s(y)), s(y)), -^#(s(x), s(y))) } Weak DPs: { leq^#(0(), y) -> c_1() , leq^#(s(x), 0()) -> c_2() , if^#(true(), x, y) -> c_4() , if^#(false(), x, y) -> c_5() , -^#(x, 0()) -> c_6() , mod^#(0(), y) -> c_8() , mod^#(s(x), 0()) -> c_9() } Weak Trs: { leq(0(), y) -> true() , leq(s(x), 0()) -> false() , leq(s(x), s(y)) -> leq(x, y) , if(true(), x, y) -> x , if(false(), x, y) -> y , -(x, 0()) -> x , -(s(x), s(y)) -> -(x, y) , mod(0(), y) -> 0() , mod(s(x), 0()) -> 0() , mod(s(x), s(y)) -> if(leq(y, x), mod(-(s(x), s(y)), s(y)), s(x)) } Obligation: innermost runtime complexity Answer: MAYBE The following weak DPs constitute a sub-graph of the DG that is closed under successors. The DPs are removed. { leq^#(0(), y) -> c_1() , leq^#(s(x), 0()) -> c_2() , if^#(true(), x, y) -> c_4() , if^#(false(), x, y) -> c_5() , -^#(x, 0()) -> c_6() , mod^#(0(), y) -> c_8() , mod^#(s(x), 0()) -> c_9() } We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { leq^#(s(x), s(y)) -> c_3(leq^#(x, y)) , -^#(s(x), s(y)) -> c_7(-^#(x, y)) , mod^#(s(x), s(y)) -> c_10(if^#(leq(y, x), mod(-(s(x), s(y)), s(y)), s(x)), leq^#(y, x), mod^#(-(s(x), s(y)), s(y)), -^#(s(x), s(y))) } Weak Trs: { leq(0(), y) -> true() , leq(s(x), 0()) -> false() , leq(s(x), s(y)) -> leq(x, y) , if(true(), x, y) -> x , if(false(), x, y) -> y , -(x, 0()) -> x , -(s(x), s(y)) -> -(x, y) , mod(0(), y) -> 0() , mod(s(x), 0()) -> 0() , mod(s(x), s(y)) -> if(leq(y, x), mod(-(s(x), s(y)), s(y)), s(x)) } Obligation: innermost runtime complexity Answer: MAYBE Due to missing edges in the dependency-graph, the right-hand sides of following rules could be simplified: { mod^#(s(x), s(y)) -> c_10(if^#(leq(y, x), mod(-(s(x), s(y)), s(y)), s(x)), leq^#(y, x), mod^#(-(s(x), s(y)), s(y)), -^#(s(x), s(y))) } We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { leq^#(s(x), s(y)) -> c_1(leq^#(x, y)) , -^#(s(x), s(y)) -> c_2(-^#(x, y)) , mod^#(s(x), s(y)) -> c_3(leq^#(y, x), mod^#(-(s(x), s(y)), s(y)), -^#(s(x), s(y))) } Weak Trs: { leq(0(), y) -> true() , leq(s(x), 0()) -> false() , leq(s(x), s(y)) -> leq(x, y) , if(true(), x, y) -> x , if(false(), x, y) -> y , -(x, 0()) -> x , -(s(x), s(y)) -> -(x, y) , mod(0(), y) -> 0() , mod(s(x), 0()) -> 0() , mod(s(x), s(y)) -> if(leq(y, x), mod(-(s(x), s(y)), s(y)), s(x)) } Obligation: innermost runtime complexity Answer: MAYBE We replace rewrite rules by usable rules: Weak Usable Rules: { -(x, 0()) -> x , -(s(x), s(y)) -> -(x, y) } We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { leq^#(s(x), s(y)) -> c_1(leq^#(x, y)) , -^#(s(x), s(y)) -> c_2(-^#(x, y)) , mod^#(s(x), s(y)) -> c_3(leq^#(y, x), mod^#(-(s(x), s(y)), s(y)), -^#(s(x), s(y))) } Weak Trs: { -(x, 0()) -> x , -(s(x), s(y)) -> -(x, y) } Obligation: innermost runtime complexity Answer: MAYBE None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'matrices' failed due to the following reason: None of the processors succeeded. Details of failed attempt(s): ----------------------------- 1) 'matrix interpretation of dimension 4' failed due to the following reason: The input cannot be shown compatible 2) 'matrix interpretation of dimension 3' failed due to the following reason: The input cannot be shown compatible 3) 'matrix interpretation of dimension 3' failed due to the following reason: The input cannot be shown compatible 4) 'matrix interpretation of dimension 2' failed due to the following reason: The input cannot be shown compatible 5) 'matrix interpretation of dimension 2' failed due to the following reason: The input cannot be shown compatible 6) 'matrix interpretation of dimension 1' failed due to the following reason: The input cannot be shown compatible 2) 'empty' failed due to the following reason: Empty strict component of the problem is NOT empty. Arrrr..