MAYBE We are left with following problem, upon which TcT provides the certificate MAYBE. Strict Trs: { minus(x, 0()) -> x , minus(s(x), s(y)) -> minus(x, y) , quot(0(), s(y)) -> 0() , quot(s(x), s(y)) -> s(quot(minus(x, y), s(y))) , app(nil(), y) -> y , app(add(n, x), y) -> add(n, app(x, y)) , reverse(nil()) -> nil() , reverse(add(n, x)) -> app(reverse(x), add(n, nil())) , shuffle(nil()) -> nil() , shuffle(add(n, x)) -> add(n, shuffle(reverse(x))) , concat(leaf(), y) -> y , concat(cons(u, v), y) -> cons(u, concat(v, y)) , less_leaves(x, leaf()) -> false() , less_leaves(leaf(), cons(w, z)) -> true() , less_leaves(cons(u, v), cons(w, z)) -> less_leaves(concat(u, v), concat(w, z)) } Obligation: innermost runtime complexity Answer: MAYBE We add following dependency tuples: Strict DPs: { minus^#(x, 0()) -> c_1() , minus^#(s(x), s(y)) -> c_2(minus^#(x, y)) , quot^#(0(), s(y)) -> c_3() , quot^#(s(x), s(y)) -> c_4(quot^#(minus(x, y), s(y)), minus^#(x, y)) , app^#(nil(), y) -> c_5() , app^#(add(n, x), y) -> c_6(app^#(x, y)) , reverse^#(nil()) -> c_7() , reverse^#(add(n, x)) -> c_8(app^#(reverse(x), add(n, nil())), reverse^#(x)) , shuffle^#(nil()) -> c_9() , shuffle^#(add(n, x)) -> c_10(shuffle^#(reverse(x)), reverse^#(x)) , concat^#(leaf(), y) -> c_11() , concat^#(cons(u, v), y) -> c_12(concat^#(v, y)) , less_leaves^#(x, leaf()) -> c_13() , less_leaves^#(leaf(), cons(w, z)) -> c_14() , less_leaves^#(cons(u, v), cons(w, z)) -> c_15(less_leaves^#(concat(u, v), concat(w, z)), concat^#(u, v), concat^#(w, z)) } and mark the set of starting terms. We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { minus^#(x, 0()) -> c_1() , minus^#(s(x), s(y)) -> c_2(minus^#(x, y)) , quot^#(0(), s(y)) -> c_3() , quot^#(s(x), s(y)) -> c_4(quot^#(minus(x, y), s(y)), minus^#(x, y)) , app^#(nil(), y) -> c_5() , app^#(add(n, x), y) -> c_6(app^#(x, y)) , reverse^#(nil()) -> c_7() , reverse^#(add(n, x)) -> c_8(app^#(reverse(x), add(n, nil())), reverse^#(x)) , shuffle^#(nil()) -> c_9() , shuffle^#(add(n, x)) -> c_10(shuffle^#(reverse(x)), reverse^#(x)) , concat^#(leaf(), y) -> c_11() , concat^#(cons(u, v), y) -> c_12(concat^#(v, y)) , less_leaves^#(x, leaf()) -> c_13() , less_leaves^#(leaf(), cons(w, z)) -> c_14() , less_leaves^#(cons(u, v), cons(w, z)) -> c_15(less_leaves^#(concat(u, v), concat(w, z)), concat^#(u, v), concat^#(w, z)) } Weak Trs: { minus(x, 0()) -> x , minus(s(x), s(y)) -> minus(x, y) , quot(0(), s(y)) -> 0() , quot(s(x), s(y)) -> s(quot(minus(x, y), s(y))) , app(nil(), y) -> y , app(add(n, x), y) -> add(n, app(x, y)) , reverse(nil()) -> nil() , reverse(add(n, x)) -> app(reverse(x), add(n, nil())) , shuffle(nil()) -> nil() , shuffle(add(n, x)) -> add(n, shuffle(reverse(x))) , concat(leaf(), y) -> y , concat(cons(u, v), y) -> cons(u, concat(v, y)) , less_leaves(x, leaf()) -> false() , less_leaves(leaf(), cons(w, z)) -> true() , less_leaves(cons(u, v), cons(w, z)) -> less_leaves(concat(u, v), concat(w, z)) } Obligation: innermost runtime complexity Answer: MAYBE We estimate the number of application of {1,3,5,7,9,11,13,14} by applications of Pre({1,3,5,7,9,11,13,14}) = {2,4,6,8,10,12,15}. Here rules are labeled as follows: DPs: { 1: minus^#(x, 0()) -> c_1() , 2: minus^#(s(x), s(y)) -> c_2(minus^#(x, y)) , 3: quot^#(0(), s(y)) -> c_3() , 4: quot^#(s(x), s(y)) -> c_4(quot^#(minus(x, y), s(y)), minus^#(x, y)) , 5: app^#(nil(), y) -> c_5() , 6: app^#(add(n, x), y) -> c_6(app^#(x, y)) , 7: reverse^#(nil()) -> c_7() , 8: reverse^#(add(n, x)) -> c_8(app^#(reverse(x), add(n, nil())), reverse^#(x)) , 9: shuffle^#(nil()) -> c_9() , 10: shuffle^#(add(n, x)) -> c_10(shuffle^#(reverse(x)), reverse^#(x)) , 11: concat^#(leaf(), y) -> c_11() , 12: concat^#(cons(u, v), y) -> c_12(concat^#(v, y)) , 13: less_leaves^#(x, leaf()) -> c_13() , 14: less_leaves^#(leaf(), cons(w, z)) -> c_14() , 15: less_leaves^#(cons(u, v), cons(w, z)) -> c_15(less_leaves^#(concat(u, v), concat(w, z)), concat^#(u, v), concat^#(w, z)) } We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { minus^#(s(x), s(y)) -> c_2(minus^#(x, y)) , quot^#(s(x), s(y)) -> c_4(quot^#(minus(x, y), s(y)), minus^#(x, y)) , app^#(add(n, x), y) -> c_6(app^#(x, y)) , reverse^#(add(n, x)) -> c_8(app^#(reverse(x), add(n, nil())), reverse^#(x)) , shuffle^#(add(n, x)) -> c_10(shuffle^#(reverse(x)), reverse^#(x)) , concat^#(cons(u, v), y) -> c_12(concat^#(v, y)) , less_leaves^#(cons(u, v), cons(w, z)) -> c_15(less_leaves^#(concat(u, v), concat(w, z)), concat^#(u, v), concat^#(w, z)) } Weak DPs: { minus^#(x, 0()) -> c_1() , quot^#(0(), s(y)) -> c_3() , app^#(nil(), y) -> c_5() , reverse^#(nil()) -> c_7() , shuffle^#(nil()) -> c_9() , concat^#(leaf(), y) -> c_11() , less_leaves^#(x, leaf()) -> c_13() , less_leaves^#(leaf(), cons(w, z)) -> c_14() } Weak Trs: { minus(x, 0()) -> x , minus(s(x), s(y)) -> minus(x, y) , quot(0(), s(y)) -> 0() , quot(s(x), s(y)) -> s(quot(minus(x, y), s(y))) , app(nil(), y) -> y , app(add(n, x), y) -> add(n, app(x, y)) , reverse(nil()) -> nil() , reverse(add(n, x)) -> app(reverse(x), add(n, nil())) , shuffle(nil()) -> nil() , shuffle(add(n, x)) -> add(n, shuffle(reverse(x))) , concat(leaf(), y) -> y , concat(cons(u, v), y) -> cons(u, concat(v, y)) , less_leaves(x, leaf()) -> false() , less_leaves(leaf(), cons(w, z)) -> true() , less_leaves(cons(u, v), cons(w, z)) -> less_leaves(concat(u, v), concat(w, z)) } Obligation: innermost runtime complexity Answer: MAYBE The following weak DPs constitute a sub-graph of the DG that is closed under successors. The DPs are removed. { minus^#(x, 0()) -> c_1() , quot^#(0(), s(y)) -> c_3() , app^#(nil(), y) -> c_5() , reverse^#(nil()) -> c_7() , shuffle^#(nil()) -> c_9() , concat^#(leaf(), y) -> c_11() , less_leaves^#(x, leaf()) -> c_13() , less_leaves^#(leaf(), cons(w, z)) -> c_14() } We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { minus^#(s(x), s(y)) -> c_2(minus^#(x, y)) , quot^#(s(x), s(y)) -> c_4(quot^#(minus(x, y), s(y)), minus^#(x, y)) , app^#(add(n, x), y) -> c_6(app^#(x, y)) , reverse^#(add(n, x)) -> c_8(app^#(reverse(x), add(n, nil())), reverse^#(x)) , shuffle^#(add(n, x)) -> c_10(shuffle^#(reverse(x)), reverse^#(x)) , concat^#(cons(u, v), y) -> c_12(concat^#(v, y)) , less_leaves^#(cons(u, v), cons(w, z)) -> c_15(less_leaves^#(concat(u, v), concat(w, z)), concat^#(u, v), concat^#(w, z)) } Weak Trs: { minus(x, 0()) -> x , minus(s(x), s(y)) -> minus(x, y) , quot(0(), s(y)) -> 0() , quot(s(x), s(y)) -> s(quot(minus(x, y), s(y))) , app(nil(), y) -> y , app(add(n, x), y) -> add(n, app(x, y)) , reverse(nil()) -> nil() , reverse(add(n, x)) -> app(reverse(x), add(n, nil())) , shuffle(nil()) -> nil() , shuffle(add(n, x)) -> add(n, shuffle(reverse(x))) , concat(leaf(), y) -> y , concat(cons(u, v), y) -> cons(u, concat(v, y)) , less_leaves(x, leaf()) -> false() , less_leaves(leaf(), cons(w, z)) -> true() , less_leaves(cons(u, v), cons(w, z)) -> less_leaves(concat(u, v), concat(w, z)) } Obligation: innermost runtime complexity Answer: MAYBE We replace rewrite rules by usable rules: Weak Usable Rules: { minus(x, 0()) -> x , minus(s(x), s(y)) -> minus(x, y) , app(nil(), y) -> y , app(add(n, x), y) -> add(n, app(x, y)) , reverse(nil()) -> nil() , reverse(add(n, x)) -> app(reverse(x), add(n, nil())) , concat(leaf(), y) -> y , concat(cons(u, v), y) -> cons(u, concat(v, y)) } We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { minus^#(s(x), s(y)) -> c_2(minus^#(x, y)) , quot^#(s(x), s(y)) -> c_4(quot^#(minus(x, y), s(y)), minus^#(x, y)) , app^#(add(n, x), y) -> c_6(app^#(x, y)) , reverse^#(add(n, x)) -> c_8(app^#(reverse(x), add(n, nil())), reverse^#(x)) , shuffle^#(add(n, x)) -> c_10(shuffle^#(reverse(x)), reverse^#(x)) , concat^#(cons(u, v), y) -> c_12(concat^#(v, y)) , less_leaves^#(cons(u, v), cons(w, z)) -> c_15(less_leaves^#(concat(u, v), concat(w, z)), concat^#(u, v), concat^#(w, z)) } Weak Trs: { minus(x, 0()) -> x , minus(s(x), s(y)) -> minus(x, y) , app(nil(), y) -> y , app(add(n, x), y) -> add(n, app(x, y)) , reverse(nil()) -> nil() , reverse(add(n, x)) -> app(reverse(x), add(n, nil())) , concat(leaf(), y) -> y , concat(cons(u, v), y) -> cons(u, concat(v, y)) } Obligation: innermost runtime complexity Answer: MAYBE The input cannot be shown compatible Arrrr..