MAYBE We are left with following problem, upon which TcT provides the certificate MAYBE. Strict Trs: { cond1(true(), x, y, z) -> cond2(gr(y, z), x, y, z) , cond2(true(), x, y, z) -> cond2(gr(y, z), x, p(y), z) , cond2(false(), x, y, z) -> cond1(gr(x, z), p(x), y, z) , gr(0(), x) -> false() , gr(s(x), 0()) -> true() , gr(s(x), s(y)) -> gr(x, y) , p(0()) -> 0() , p(s(x)) -> x } Obligation: innermost runtime complexity Answer: MAYBE We add following dependency tuples: Strict DPs: { cond1^#(true(), x, y, z) -> c_1(cond2^#(gr(y, z), x, y, z), gr^#(y, z)) , cond2^#(true(), x, y, z) -> c_2(cond2^#(gr(y, z), x, p(y), z), gr^#(y, z), p^#(y)) , cond2^#(false(), x, y, z) -> c_3(cond1^#(gr(x, z), p(x), y, z), gr^#(x, z), p^#(x)) , gr^#(0(), x) -> c_4() , gr^#(s(x), 0()) -> c_5() , gr^#(s(x), s(y)) -> c_6(gr^#(x, y)) , p^#(0()) -> c_7() , p^#(s(x)) -> c_8() } and mark the set of starting terms. We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { cond1^#(true(), x, y, z) -> c_1(cond2^#(gr(y, z), x, y, z), gr^#(y, z)) , cond2^#(true(), x, y, z) -> c_2(cond2^#(gr(y, z), x, p(y), z), gr^#(y, z), p^#(y)) , cond2^#(false(), x, y, z) -> c_3(cond1^#(gr(x, z), p(x), y, z), gr^#(x, z), p^#(x)) , gr^#(0(), x) -> c_4() , gr^#(s(x), 0()) -> c_5() , gr^#(s(x), s(y)) -> c_6(gr^#(x, y)) , p^#(0()) -> c_7() , p^#(s(x)) -> c_8() } Weak Trs: { cond1(true(), x, y, z) -> cond2(gr(y, z), x, y, z) , cond2(true(), x, y, z) -> cond2(gr(y, z), x, p(y), z) , cond2(false(), x, y, z) -> cond1(gr(x, z), p(x), y, z) , gr(0(), x) -> false() , gr(s(x), 0()) -> true() , gr(s(x), s(y)) -> gr(x, y) , p(0()) -> 0() , p(s(x)) -> x } Obligation: innermost runtime complexity Answer: MAYBE We estimate the number of application of {4,5,7,8} by applications of Pre({4,5,7,8}) = {1,2,3,6}. Here rules are labeled as follows: DPs: { 1: cond1^#(true(), x, y, z) -> c_1(cond2^#(gr(y, z), x, y, z), gr^#(y, z)) , 2: cond2^#(true(), x, y, z) -> c_2(cond2^#(gr(y, z), x, p(y), z), gr^#(y, z), p^#(y)) , 3: cond2^#(false(), x, y, z) -> c_3(cond1^#(gr(x, z), p(x), y, z), gr^#(x, z), p^#(x)) , 4: gr^#(0(), x) -> c_4() , 5: gr^#(s(x), 0()) -> c_5() , 6: gr^#(s(x), s(y)) -> c_6(gr^#(x, y)) , 7: p^#(0()) -> c_7() , 8: p^#(s(x)) -> c_8() } We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { cond1^#(true(), x, y, z) -> c_1(cond2^#(gr(y, z), x, y, z), gr^#(y, z)) , cond2^#(true(), x, y, z) -> c_2(cond2^#(gr(y, z), x, p(y), z), gr^#(y, z), p^#(y)) , cond2^#(false(), x, y, z) -> c_3(cond1^#(gr(x, z), p(x), y, z), gr^#(x, z), p^#(x)) , gr^#(s(x), s(y)) -> c_6(gr^#(x, y)) } Weak DPs: { gr^#(0(), x) -> c_4() , gr^#(s(x), 0()) -> c_5() , p^#(0()) -> c_7() , p^#(s(x)) -> c_8() } Weak Trs: { cond1(true(), x, y, z) -> cond2(gr(y, z), x, y, z) , cond2(true(), x, y, z) -> cond2(gr(y, z), x, p(y), z) , cond2(false(), x, y, z) -> cond1(gr(x, z), p(x), y, z) , gr(0(), x) -> false() , gr(s(x), 0()) -> true() , gr(s(x), s(y)) -> gr(x, y) , p(0()) -> 0() , p(s(x)) -> x } Obligation: innermost runtime complexity Answer: MAYBE The following weak DPs constitute a sub-graph of the DG that is closed under successors. The DPs are removed. { gr^#(0(), x) -> c_4() , gr^#(s(x), 0()) -> c_5() , p^#(0()) -> c_7() , p^#(s(x)) -> c_8() } We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { cond1^#(true(), x, y, z) -> c_1(cond2^#(gr(y, z), x, y, z), gr^#(y, z)) , cond2^#(true(), x, y, z) -> c_2(cond2^#(gr(y, z), x, p(y), z), gr^#(y, z), p^#(y)) , cond2^#(false(), x, y, z) -> c_3(cond1^#(gr(x, z), p(x), y, z), gr^#(x, z), p^#(x)) , gr^#(s(x), s(y)) -> c_6(gr^#(x, y)) } Weak Trs: { cond1(true(), x, y, z) -> cond2(gr(y, z), x, y, z) , cond2(true(), x, y, z) -> cond2(gr(y, z), x, p(y), z) , cond2(false(), x, y, z) -> cond1(gr(x, z), p(x), y, z) , gr(0(), x) -> false() , gr(s(x), 0()) -> true() , gr(s(x), s(y)) -> gr(x, y) , p(0()) -> 0() , p(s(x)) -> x } Obligation: innermost runtime complexity Answer: MAYBE Due to missing edges in the dependency-graph, the right-hand sides of following rules could be simplified: { cond2^#(true(), x, y, z) -> c_2(cond2^#(gr(y, z), x, p(y), z), gr^#(y, z), p^#(y)) , cond2^#(false(), x, y, z) -> c_3(cond1^#(gr(x, z), p(x), y, z), gr^#(x, z), p^#(x)) } We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { cond1^#(true(), x, y, z) -> c_1(cond2^#(gr(y, z), x, y, z), gr^#(y, z)) , cond2^#(true(), x, y, z) -> c_2(cond2^#(gr(y, z), x, p(y), z), gr^#(y, z)) , cond2^#(false(), x, y, z) -> c_3(cond1^#(gr(x, z), p(x), y, z), gr^#(x, z)) , gr^#(s(x), s(y)) -> c_4(gr^#(x, y)) } Weak Trs: { cond1(true(), x, y, z) -> cond2(gr(y, z), x, y, z) , cond2(true(), x, y, z) -> cond2(gr(y, z), x, p(y), z) , cond2(false(), x, y, z) -> cond1(gr(x, z), p(x), y, z) , gr(0(), x) -> false() , gr(s(x), 0()) -> true() , gr(s(x), s(y)) -> gr(x, y) , p(0()) -> 0() , p(s(x)) -> x } Obligation: innermost runtime complexity Answer: MAYBE We replace rewrite rules by usable rules: Weak Usable Rules: { gr(0(), x) -> false() , gr(s(x), 0()) -> true() , gr(s(x), s(y)) -> gr(x, y) , p(0()) -> 0() , p(s(x)) -> x } We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { cond1^#(true(), x, y, z) -> c_1(cond2^#(gr(y, z), x, y, z), gr^#(y, z)) , cond2^#(true(), x, y, z) -> c_2(cond2^#(gr(y, z), x, p(y), z), gr^#(y, z)) , cond2^#(false(), x, y, z) -> c_3(cond1^#(gr(x, z), p(x), y, z), gr^#(x, z)) , gr^#(s(x), s(y)) -> c_4(gr^#(x, y)) } Weak Trs: { gr(0(), x) -> false() , gr(s(x), 0()) -> true() , gr(s(x), s(y)) -> gr(x, y) , p(0()) -> 0() , p(s(x)) -> x } Obligation: innermost runtime complexity Answer: MAYBE The input cannot be shown compatible Arrrr..