YES(O(1),O(n^1)) We are left with following problem, upon which TcT provides the certificate YES(O(1),O(n^1)). Strict Trs: { f(s(X)) -> f(X) , g(cons(s(X), Y)) -> s(X) , g(cons(0(), Y)) -> g(Y) , h(cons(X, Y)) -> h(g(cons(X, Y))) } Obligation: innermost runtime complexity Answer: YES(O(1),O(n^1)) We add following weak dependency pairs: Strict DPs: { f^#(s(X)) -> c_1(f^#(X)) , g^#(cons(s(X), Y)) -> c_2() , g^#(cons(0(), Y)) -> c_3(g^#(Y)) , h^#(cons(X, Y)) -> c_4(h^#(g(cons(X, Y)))) } and mark the set of starting terms. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(n^1)). Strict DPs: { f^#(s(X)) -> c_1(f^#(X)) , g^#(cons(s(X), Y)) -> c_2() , g^#(cons(0(), Y)) -> c_3(g^#(Y)) , h^#(cons(X, Y)) -> c_4(h^#(g(cons(X, Y)))) } Strict Trs: { f(s(X)) -> f(X) , g(cons(s(X), Y)) -> s(X) , g(cons(0(), Y)) -> g(Y) , h(cons(X, Y)) -> h(g(cons(X, Y))) } Obligation: innermost runtime complexity Answer: YES(O(1),O(n^1)) We replace rewrite rules by usable rules: Strict Usable Rules: { g(cons(s(X), Y)) -> s(X) , g(cons(0(), Y)) -> g(Y) } We are left with following problem, upon which TcT provides the certificate YES(O(1),O(n^1)). Strict DPs: { f^#(s(X)) -> c_1(f^#(X)) , g^#(cons(s(X), Y)) -> c_2() , g^#(cons(0(), Y)) -> c_3(g^#(Y)) , h^#(cons(X, Y)) -> c_4(h^#(g(cons(X, Y)))) } Strict Trs: { g(cons(s(X), Y)) -> s(X) , g(cons(0(), Y)) -> g(Y) } Obligation: innermost runtime complexity Answer: YES(O(1),O(n^1)) The weightgap principle applies (using the following constant growth matrix-interpretation) The following argument positions are usable: Uargs(c_1) = {1}, Uargs(c_3) = {1}, Uargs(h^#) = {1}, Uargs(c_4) = {1} TcT has computed following constructor-restricted matrix interpretation. [s](x1) = [1] x1 + [2] [g](x1) = [1] x1 + [2] [cons](x1, x2) = [1] x1 + [1] x2 + [0] [0] = [1] [f^#](x1) = [1] x1 + [2] [c_1](x1) = [1] x1 + [1] [g^#](x1) = [2] x1 + [2] [c_2] = [1] [c_3](x1) = [1] x1 + [1] [h^#](x1) = [2] x1 + [2] [c_4](x1) = [1] x1 + [1] This order satisfies following ordering constraints: [g(cons(s(X), Y))] = [1] X + [1] Y + [4] > [1] X + [2] = [s(X)] [g(cons(0(), Y))] = [1] Y + [3] > [1] Y + [2] = [g(Y)] Further, it can be verified that all rules not oriented are covered by the weightgap condition. We are left with following problem, upon which TcT provides the certificate YES(?,O(1)). Strict DPs: { h^#(cons(X, Y)) -> c_4(h^#(g(cons(X, Y)))) } Weak DPs: { f^#(s(X)) -> c_1(f^#(X)) , g^#(cons(s(X), Y)) -> c_2() , g^#(cons(0(), Y)) -> c_3(g^#(Y)) } Weak Trs: { g(cons(s(X), Y)) -> s(X) , g(cons(0(), Y)) -> g(Y) } Obligation: innermost runtime complexity Answer: YES(?,O(1)) We estimate the number of application of {1} by applications of Pre({1}) = {}. Here rules are labeled as follows: DPs: { 1: h^#(cons(X, Y)) -> c_4(h^#(g(cons(X, Y)))) , 2: f^#(s(X)) -> c_1(f^#(X)) , 3: g^#(cons(s(X), Y)) -> c_2() , 4: g^#(cons(0(), Y)) -> c_3(g^#(Y)) } We are left with following problem, upon which TcT provides the certificate YES(?,O(1)). Weak DPs: { f^#(s(X)) -> c_1(f^#(X)) , g^#(cons(s(X), Y)) -> c_2() , g^#(cons(0(), Y)) -> c_3(g^#(Y)) , h^#(cons(X, Y)) -> c_4(h^#(g(cons(X, Y)))) } Weak Trs: { g(cons(s(X), Y)) -> s(X) , g(cons(0(), Y)) -> g(Y) } Obligation: innermost runtime complexity Answer: YES(?,O(1)) The following weak DPs constitute a sub-graph of the DG that is closed under successors. The DPs are removed. { f^#(s(X)) -> c_1(f^#(X)) , g^#(cons(s(X), Y)) -> c_2() , g^#(cons(0(), Y)) -> c_3(g^#(Y)) , h^#(cons(X, Y)) -> c_4(h^#(g(cons(X, Y)))) } We are left with following problem, upon which TcT provides the certificate YES(?,O(1)). Weak Trs: { g(cons(s(X), Y)) -> s(X) , g(cons(0(), Y)) -> g(Y) } Obligation: innermost runtime complexity Answer: YES(?,O(1)) No rule is usable, rules are removed from the input problem. We are left with following problem, upon which TcT provides the certificate YES(?,O(1)). Rules: Empty Obligation: innermost runtime complexity Answer: YES(?,O(1)) The input was oriented with the instance of 'Small Polynomial Path Order (PS)' as induced by the safe mapping and precedence empty . Following symbols are considered recursive: {} The recursion depth is 0. Further, following argument filtering is employed: empty Usable defined function symbols are a subset of: {} For your convenience, here are the satisfied ordering constraints: Hurray, we answered YES(O(1),O(n^1))