MAYBE We are left with following problem, upon which TcT provides the certificate MAYBE. Strict Trs: { f(x, 0(), 0()) -> s(x) , f(0(), y, 0()) -> s(y) , f(0(), 0(), z) -> s(z) , f(0(), s(0()), s(0())) -> s(s(0())) , f(0(), s(0()), s(s(z))) -> f(0(), s(0()), z) , f(0(), s(s(y)), s(0())) -> f(0(), y, s(0())) , f(0(), s(s(y)), s(s(z))) -> f(0(), y, f(0(), s(s(y)), s(z))) , f(s(x), 0(), s(z)) -> f(x, s(0()), z) , f(s(x), s(y), 0()) -> f(x, y, s(0())) , f(s(x), s(y), s(z)) -> f(x, y, f(s(x), s(y), z)) , f(s(0()), y, z) -> f(0(), s(y), s(z)) } Obligation: innermost runtime complexity Answer: MAYBE We add following dependency tuples: Strict DPs: { f^#(x, 0(), 0()) -> c_1() , f^#(0(), y, 0()) -> c_2() , f^#(0(), 0(), z) -> c_3() , f^#(0(), s(0()), s(0())) -> c_4() , f^#(0(), s(0()), s(s(z))) -> c_5(f^#(0(), s(0()), z)) , f^#(0(), s(s(y)), s(0())) -> c_6(f^#(0(), y, s(0()))) , f^#(0(), s(s(y)), s(s(z))) -> c_7(f^#(0(), y, f(0(), s(s(y)), s(z))), f^#(0(), s(s(y)), s(z))) , f^#(s(x), 0(), s(z)) -> c_8(f^#(x, s(0()), z)) , f^#(s(x), s(y), 0()) -> c_9(f^#(x, y, s(0()))) , f^#(s(x), s(y), s(z)) -> c_10(f^#(x, y, f(s(x), s(y), z)), f^#(s(x), s(y), z)) , f^#(s(0()), y, z) -> c_11(f^#(0(), s(y), s(z))) } and mark the set of starting terms. We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { f^#(x, 0(), 0()) -> c_1() , f^#(0(), y, 0()) -> c_2() , f^#(0(), 0(), z) -> c_3() , f^#(0(), s(0()), s(0())) -> c_4() , f^#(0(), s(0()), s(s(z))) -> c_5(f^#(0(), s(0()), z)) , f^#(0(), s(s(y)), s(0())) -> c_6(f^#(0(), y, s(0()))) , f^#(0(), s(s(y)), s(s(z))) -> c_7(f^#(0(), y, f(0(), s(s(y)), s(z))), f^#(0(), s(s(y)), s(z))) , f^#(s(x), 0(), s(z)) -> c_8(f^#(x, s(0()), z)) , f^#(s(x), s(y), 0()) -> c_9(f^#(x, y, s(0()))) , f^#(s(x), s(y), s(z)) -> c_10(f^#(x, y, f(s(x), s(y), z)), f^#(s(x), s(y), z)) , f^#(s(0()), y, z) -> c_11(f^#(0(), s(y), s(z))) } Weak Trs: { f(x, 0(), 0()) -> s(x) , f(0(), y, 0()) -> s(y) , f(0(), 0(), z) -> s(z) , f(0(), s(0()), s(0())) -> s(s(0())) , f(0(), s(0()), s(s(z))) -> f(0(), s(0()), z) , f(0(), s(s(y)), s(0())) -> f(0(), y, s(0())) , f(0(), s(s(y)), s(s(z))) -> f(0(), y, f(0(), s(s(y)), s(z))) , f(s(x), 0(), s(z)) -> f(x, s(0()), z) , f(s(x), s(y), 0()) -> f(x, y, s(0())) , f(s(x), s(y), s(z)) -> f(x, y, f(s(x), s(y), z)) , f(s(0()), y, z) -> f(0(), s(y), s(z)) } Obligation: innermost runtime complexity Answer: MAYBE We estimate the number of application of {1,2,3,4} by applications of Pre({1,2,3,4}) = {5,6,7,8,9,10,11}. Here rules are labeled as follows: DPs: { 1: f^#(x, 0(), 0()) -> c_1() , 2: f^#(0(), y, 0()) -> c_2() , 3: f^#(0(), 0(), z) -> c_3() , 4: f^#(0(), s(0()), s(0())) -> c_4() , 5: f^#(0(), s(0()), s(s(z))) -> c_5(f^#(0(), s(0()), z)) , 6: f^#(0(), s(s(y)), s(0())) -> c_6(f^#(0(), y, s(0()))) , 7: f^#(0(), s(s(y)), s(s(z))) -> c_7(f^#(0(), y, f(0(), s(s(y)), s(z))), f^#(0(), s(s(y)), s(z))) , 8: f^#(s(x), 0(), s(z)) -> c_8(f^#(x, s(0()), z)) , 9: f^#(s(x), s(y), 0()) -> c_9(f^#(x, y, s(0()))) , 10: f^#(s(x), s(y), s(z)) -> c_10(f^#(x, y, f(s(x), s(y), z)), f^#(s(x), s(y), z)) , 11: f^#(s(0()), y, z) -> c_11(f^#(0(), s(y), s(z))) } We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { f^#(0(), s(0()), s(s(z))) -> c_5(f^#(0(), s(0()), z)) , f^#(0(), s(s(y)), s(0())) -> c_6(f^#(0(), y, s(0()))) , f^#(0(), s(s(y)), s(s(z))) -> c_7(f^#(0(), y, f(0(), s(s(y)), s(z))), f^#(0(), s(s(y)), s(z))) , f^#(s(x), 0(), s(z)) -> c_8(f^#(x, s(0()), z)) , f^#(s(x), s(y), 0()) -> c_9(f^#(x, y, s(0()))) , f^#(s(x), s(y), s(z)) -> c_10(f^#(x, y, f(s(x), s(y), z)), f^#(s(x), s(y), z)) , f^#(s(0()), y, z) -> c_11(f^#(0(), s(y), s(z))) } Weak DPs: { f^#(x, 0(), 0()) -> c_1() , f^#(0(), y, 0()) -> c_2() , f^#(0(), 0(), z) -> c_3() , f^#(0(), s(0()), s(0())) -> c_4() } Weak Trs: { f(x, 0(), 0()) -> s(x) , f(0(), y, 0()) -> s(y) , f(0(), 0(), z) -> s(z) , f(0(), s(0()), s(0())) -> s(s(0())) , f(0(), s(0()), s(s(z))) -> f(0(), s(0()), z) , f(0(), s(s(y)), s(0())) -> f(0(), y, s(0())) , f(0(), s(s(y)), s(s(z))) -> f(0(), y, f(0(), s(s(y)), s(z))) , f(s(x), 0(), s(z)) -> f(x, s(0()), z) , f(s(x), s(y), 0()) -> f(x, y, s(0())) , f(s(x), s(y), s(z)) -> f(x, y, f(s(x), s(y), z)) , f(s(0()), y, z) -> f(0(), s(y), s(z)) } Obligation: innermost runtime complexity Answer: MAYBE The following weak DPs constitute a sub-graph of the DG that is closed under successors. The DPs are removed. { f^#(x, 0(), 0()) -> c_1() , f^#(0(), y, 0()) -> c_2() , f^#(0(), 0(), z) -> c_3() , f^#(0(), s(0()), s(0())) -> c_4() } We are left with following problem, upon which TcT provides the certificate MAYBE. Strict DPs: { f^#(0(), s(0()), s(s(z))) -> c_5(f^#(0(), s(0()), z)) , f^#(0(), s(s(y)), s(0())) -> c_6(f^#(0(), y, s(0()))) , f^#(0(), s(s(y)), s(s(z))) -> c_7(f^#(0(), y, f(0(), s(s(y)), s(z))), f^#(0(), s(s(y)), s(z))) , f^#(s(x), 0(), s(z)) -> c_8(f^#(x, s(0()), z)) , f^#(s(x), s(y), 0()) -> c_9(f^#(x, y, s(0()))) , f^#(s(x), s(y), s(z)) -> c_10(f^#(x, y, f(s(x), s(y), z)), f^#(s(x), s(y), z)) , f^#(s(0()), y, z) -> c_11(f^#(0(), s(y), s(z))) } Weak Trs: { f(x, 0(), 0()) -> s(x) , f(0(), y, 0()) -> s(y) , f(0(), 0(), z) -> s(z) , f(0(), s(0()), s(0())) -> s(s(0())) , f(0(), s(0()), s(s(z))) -> f(0(), s(0()), z) , f(0(), s(s(y)), s(0())) -> f(0(), y, s(0())) , f(0(), s(s(y)), s(s(z))) -> f(0(), y, f(0(), s(s(y)), s(z))) , f(s(x), 0(), s(z)) -> f(x, s(0()), z) , f(s(x), s(y), 0()) -> f(x, y, s(0())) , f(s(x), s(y), s(z)) -> f(x, y, f(s(x), s(y), z)) , f(s(0()), y, z) -> f(0(), s(y), s(z)) } Obligation: innermost runtime complexity Answer: MAYBE The input cannot be shown compatible Arrrr..