YES(O(1),O(n^1)) We are left with following problem, upon which TcT provides the certificate YES(O(1),O(n^1)). Strict Trs: { a__c() -> a__f(g(c())) , a__c() -> c() , a__f(X) -> f(X) , a__f(g(X)) -> g(X) , mark(g(X)) -> g(X) , mark(c()) -> a__c() , mark(f(X)) -> a__f(X) } Obligation: innermost runtime complexity Answer: YES(O(1),O(n^1)) We add following weak dependency pairs: Strict DPs: { a__c^#() -> c_1(a__f^#(g(c()))) , a__c^#() -> c_2() , a__f^#(X) -> c_3() , a__f^#(g(X)) -> c_4() , mark^#(g(X)) -> c_5() , mark^#(c()) -> c_6(a__c^#()) , mark^#(f(X)) -> c_7(a__f^#(X)) } and mark the set of starting terms. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(n^1)). Strict DPs: { a__c^#() -> c_1(a__f^#(g(c()))) , a__c^#() -> c_2() , a__f^#(X) -> c_3() , a__f^#(g(X)) -> c_4() , mark^#(g(X)) -> c_5() , mark^#(c()) -> c_6(a__c^#()) , mark^#(f(X)) -> c_7(a__f^#(X)) } Strict Trs: { a__c() -> a__f(g(c())) , a__c() -> c() , a__f(X) -> f(X) , a__f(g(X)) -> g(X) , mark(g(X)) -> g(X) , mark(c()) -> a__c() , mark(f(X)) -> a__f(X) } Obligation: innermost runtime complexity Answer: YES(O(1),O(n^1)) No rule is usable, rules are removed from the input problem. We are left with following problem, upon which TcT provides the certificate YES(O(1),O(n^1)). Strict DPs: { a__c^#() -> c_1(a__f^#(g(c()))) , a__c^#() -> c_2() , a__f^#(X) -> c_3() , a__f^#(g(X)) -> c_4() , mark^#(g(X)) -> c_5() , mark^#(c()) -> c_6(a__c^#()) , mark^#(f(X)) -> c_7(a__f^#(X)) } Obligation: innermost runtime complexity Answer: YES(O(1),O(n^1)) The weightgap principle applies (using the following constant growth matrix-interpretation) The following argument positions are usable: Uargs(c_1) = {1}, Uargs(c_6) = {1}, Uargs(c_7) = {1} TcT has computed following constructor-restricted matrix interpretation. [g](x1) = [1] x1 + [1] [c] = [1] [f](x1) = [1] x1 + [2] [a__c^#] = [1] [c_1](x1) = [1] x1 + [2] [a__f^#](x1) = [1] x1 + [2] [c_2] = [0] [c_3] = [1] [c_4] = [2] [mark^#](x1) = [1] x1 + [2] [c_5] = [2] [c_6](x1) = [1] x1 + [1] [c_7](x1) = [1] x1 + [1] This order satisfies following ordering constraints: Further, it can be verified that all rules not oriented are covered by the weightgap condition. We are left with following problem, upon which TcT provides the certificate YES(?,O(1)). Strict DPs: { a__c^#() -> c_1(a__f^#(g(c()))) } Weak DPs: { a__c^#() -> c_2() , a__f^#(X) -> c_3() , a__f^#(g(X)) -> c_4() , mark^#(g(X)) -> c_5() , mark^#(c()) -> c_6(a__c^#()) , mark^#(f(X)) -> c_7(a__f^#(X)) } Obligation: innermost runtime complexity Answer: YES(?,O(1)) The following weak DPs constitute a sub-graph of the DG that is closed under successors. The DPs are removed. { a__c^#() -> c_2() , a__f^#(X) -> c_3() , a__f^#(g(X)) -> c_4() , mark^#(g(X)) -> c_5() , mark^#(f(X)) -> c_7(a__f^#(X)) } We are left with following problem, upon which TcT provides the certificate YES(?,O(1)). Strict DPs: { a__c^#() -> c_1(a__f^#(g(c()))) } Weak DPs: { mark^#(c()) -> c_6(a__c^#()) } Obligation: innermost runtime complexity Answer: YES(?,O(1)) Due to missing edges in the dependency-graph, the right-hand sides of following rules could be simplified: { a__c^#() -> c_1(a__f^#(g(c()))) } We are left with following problem, upon which TcT provides the certificate YES(?,O(1)). Strict DPs: { a__c^#() -> c_1() } Weak DPs: { mark^#(c()) -> c_2(a__c^#()) } Obligation: innermost runtime complexity Answer: YES(?,O(1)) Consider the dependency graph 1: a__c^#() -> c_1() 2: mark^#(c()) -> c_2(a__c^#()) -->_1 a__c^#() -> c_1() :1 Following roots of the dependency graph are removed, as the considered set of starting terms is closed under reduction with respect to these rules (modulo compound contexts). { mark^#(c()) -> c_2(a__c^#()) } We are left with following problem, upon which TcT provides the certificate YES(?,O(1)). Strict DPs: { a__c^#() -> c_1() } Obligation: innermost runtime complexity Answer: YES(?,O(1)) Consider the dependency graph 1: a__c^#() -> c_1() Following roots of the dependency graph are removed, as the considered set of starting terms is closed under reduction with respect to these rules (modulo compound contexts). { a__c^#() -> c_1() } We are left with following problem, upon which TcT provides the certificate YES(?,O(1)). Rules: Empty Obligation: innermost runtime complexity Answer: YES(?,O(1)) The input was oriented with the instance of 'Small Polynomial Path Order (PS)' as induced by the safe mapping and precedence empty . Following symbols are considered recursive: {} The recursion depth is 0. Further, following argument filtering is employed: empty Usable defined function symbols are a subset of: {} For your convenience, here are the satisfied ordering constraints: Hurray, we answered YES(O(1),O(n^1))