YES
O(n^2)
TRS:
 {b(b(a(x))) -> a(b(b(x))),
     a(a(x)) -> b(b(x))}
 DUP: We consider a non-duplicating system.
  Trs:
   {b(b(a(x))) -> a(b(b(x))),
       a(a(x)) -> b(b(x))}
  Matrix Interpretation:
   Interpretation class: triangular
       [X1]    [1 1][X1]   [0]
   [a]([X0]) = [0 1][X0] + [1]
   
       [X1]    [1 1][X1]   [0]
   [b]([X0]) = [0 1][X0] + [0]
   
   
   Qed